Question

this is tough one, is prob..

In one version of a popular lottery
game, a player selects six of the numbers from 1 to 54.
The agency in charge of the lottery also selects six numbers.
What is the probability that the player will match the six
numbers if two50¢ tickets are purchased? (This jackpot is
worth at least $2 million in prize money and grows according
to the number of tickets sold.)

Answer 1

I'm not good in probability please help

Answer 2

Can a number be choose twice from 1 to 54?

Answer 3

i guess so

Answer 4

so on a smaller example
if I could choose 2 numbers from1 through 4 (and I could choose a number from 1 through 4 more than once)
Some combinations could be:
11
12
13
14
21
22
23
24
31
32
33
34
41
42
43
44
That is how many combinations: 4(4)=16.
Which makes since. Because there are 4 ways you can choose the first number and 4 ways to choose the second number.

Now one of these 16 will match the combination chosen by the people who run the lottery.
So the probability of your combination being selected should be 1/16 for this example.
right?

Answer 5

but i don't get it

Answer 6

c(n,k) =\[\frac{ n! }{ k!(n-k)! }\]

Answer 7

it wouldn't be : \[\frac{ 54....48! }{ 6!(48!) }\]

Answer 8

?

Answer 9

you said I could choose a number more than once right?

Answer 10

im lost

Answer 11

why is my aproach wrong ?

Answer 12

ok yeah . .

Answer 13

oops
sorry
54*54*54*54*54*54 is what i meant

Answer 14

54^6

Answer 15

just like on the smaller example we did 4*4
because we could select 4 numbers both both picks

Answer 16

but what you are saying is not a permutation with repetition?

Answer 17

I'm going off what you told me....
You said we could choose a number more than once.

Answer 18

So you could choose 54 54 54 54 54 54
or 54 54 54 53
or so on...

Answer 19

54 54 54 54 54 53*

Answer 20

take it easy. well isaid that because i assumed the question says that

Answer 21

could just we get the point

Answer 22

I'm not upset. I'm just telling you that you told me that we could repeat a number.

Answer 23

well i guess you read the problem too

Answer 24

I was asking to clarify the problem. I have never done the lottery thing so I don't know how the lottery works. Can we pick a number more than once for our six numbers?

Answer 25

Does the order matter in which we pick them?

Answer 26

i know some of the principles, i just don't know how use the tools

Answer 27

well is possible but you know the chances are so low

Answer 28

it is possible the order doesn't matter in your problem?

Answer 29

I would have to read how the lottery works I guess.

Answer 30

br b

Answer 31

\[\Delta = \left[\begin{matrix}a & -b \\ a & b\end{matrix}\right]\]

Answer 32

\[x=\left[\begin{matrix}-1 & -b\\ 7& b\end{matrix}\right]\]/ delta
\[y =\left[\begin{matrix}a & r \\ a& 7\end{matrix}\right]/ \Delta\]