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Mathematics 21 Online
OpenStudy (luigi0210):

Find the relative growth rate. (Assume t is measured in hours.)

OpenStudy (luigi0210):

A common inhabitant of human intestines is the bacterium \(Escherichia~coli\). A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 64 cells.

OpenStudy (anonymous):

do you know the formula?

OpenStudy (rock_mit182):

\[y = 60 t ^{\frac{ 1 }{ 3 }}\]

OpenStudy (rock_mit182):

i mean the initial would be 64

OpenStudy (luigi0210):

Nope, I don't know it.. totally new and haven't been taught it yet. And you sure? So the the initial is 64?

OpenStudy (solomonzelman):

that's what your q states (at least)

OpenStudy (solomonzelman):

Am I good at googling ? http://answers.yahoo.com/question/index?qid=20080316183032AA2lJBD

OpenStudy (ikram002p):

well its clear if t is the time then at t_0=0 f(0)=64 at t(20) f(20)=64^2 and so on ...

OpenStudy (rock_mit182):

20 minutes is \[\frac{ 1 }{ 3 }\] of a hour

OpenStudy (rock_mit182):

but im not completly sure about the exponent, it could be . .

OpenStudy (luigi0210):

@SolomonZelman You're good at googling but the answers are wrong xD

OpenStudy (ikram002p):

hmm so the population f(t) would be \(\large f(t)=f(0)e^{kt}\) f(0)=64 hmm as t in hour so yes its 1/3 for 20 min now we need to find k using \(\large f(1/3)=64 * e^{1/3k}\) ohh and f(1/3)=64*2 (not as i mintioned before ) solve for k so u would have the population function and the relative growth rate would be k !

OpenStudy (anonymous):

Formula A = P (2)^(t/h) A = final population P = initial population t = time h = time it takes to double In this case, A = 64(2)^(t/20), where t is in minutes

OpenStudy (ikram002p):

and what is the the relative growth rate @sourwing :o

OpenStudy (anonymous):

set e^r = 2^(1/20) and solve for r

OpenStudy (anonymous):

r = 0.03465 or 3.465%. relative rate in different time unit will certainly be different.

OpenStudy (anonymous):

in hours,rate is e^r = e^(1/(20/60)) r = 0.23105 or 23.105%

OpenStudy (anonymous):

typo, it's e^r = 2^(1/(20/60))

OpenStudy (anonymous):

relative rate is still correct

OpenStudy (ikram002p):

ive got 2.079 hmm idk maby there is somthing wrong with my answer

OpenStudy (anonymous):

opps. the equation was right, i did the math wrong :DD e^r = 2^(1/(20/60)), then r = 2.079 %

OpenStudy (ikram002p):

so were both are correct ^_^

OpenStudy (anonymous):

yep ^.-b

OpenStudy (ikram002p):

:D

OpenStudy (luigi0210):

Tried following along and makes sense now, thanks guys :D

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