please help.....
with wat?
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27 and 3 pizzas
\[\cot (\sin^{-1} (\frac{ 7 }{ 25 }))\]
please help....im desperate
\(\bf cot\left[sin^{-1}\left(\frac{ 7 }{ 25 }\right)\right] \\ \quad \\ \quad \\ sin^{-1}\left(\frac{ 7 }{ 25 }\right)=\theta\implies sin(\theta)=\cfrac{ 7 }{ 25 }\implies \cfrac{opposite}{hypotenuse}\implies \cfrac{b=7}{c=25}\) |dw:1395265139001:dw| recall that \(\bf \)
hmmm
recall that -> \(\bf cot(\theta)=\cfrac{adjacent}{opposite}\implies \cfrac{a}{b}\)
Hints: Define sin x. Sin x is the ratio of ? to ? Draw that angle x in the first quadrant. Your drawing should show that the side opposite the angle x is 7 (the opposite side), and that the hypotenuse is 25. Calculate the third side. Use the Pyth. Thm. Look at the resulting triangle. Review how the contangent function is defined. then write the cotangent function, using info directly from your illustration.
so the answer is \[\frac{ 24 }{ 7 }\]
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