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Chemistry 26 Online
OpenStudy (anonymous):

REDOX Which one of the following is a redox reaction? 2 Na(g) + Cl2(g) 2 NaCl(s) K2Cr2O7(aq) + 2 KOH(aq) 2 K2CrO4(aq) + H2O(l) H2O(l) H+(aq) + OH -(aq) Na2CO3(s) + 2 HCl(aq) 2 NaCl(aq) + CO2(g) + H2O(l) Ba2+(aq) + SO42-(aq) BaSO4(s) The answer is the first but take me step by step.

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (anonymous):

yepp ill look at Khan but ya heres something better to explain

OpenStudy (ipwnbunnies):

I can barely teach precipitation reactions, I'll barely be a help on redox reactions.

OpenStudy (ipwnbunnies):

Check out some lessons on redox reactions. I need help with these when I first learned them, I found great videos online that explained them.

OpenStudy (ipwnbunnies):

needed*

OpenStudy (anonymous):

bro. I know how to find their charges and stuff. I knwo this. but I dont know if it's a redox if the charge changes or what.

OpenStudy (ipwnbunnies):

The oxidation numbers are the biggest thing to worry about. Well, first you need to know at least something about a redox reaction.

OpenStudy (anonymous):

i know what Reducing agent and oxidizing agent are and that stuff. for a redox, is it when the charge changes in one of the elements or stays the same?

OpenStudy (ipwnbunnies):

When the oxidation # of a substance increases from the reactant side to the product side, the substance is oxidized and loses electrons.

OpenStudy (ipwnbunnies):

Another thing to think about, can you cancel any of the choices out?

OpenStudy (ipwnbunnies):

Honestly, I'm not the guy that can explain this that well.

OpenStudy (anonymous):

ok ohhhhh i have one that you may be able to solve! you good with oxidation numbers?

OpenStudy (ipwnbunnies):

Barely.

OpenStudy (ipwnbunnies):

Like, I know the answer to the question b/c I know one of the polyatomic ions in one of the answer is a pretty good oxidizer.

OpenStudy (anonymous):

Give the oxidation number of nitrogen in each of the following NH4+ ok so I know it's suppose to be balanced. but the answer is -3. I got -4 because H is +1 and 4 x 1= 4. but idk why it's -3. do you know?

OpenStudy (ipwnbunnies):

Yes, because when it comes to numbers, a polyatomic ion's oxidation number is the same as their charge.

OpenStudy (ipwnbunnies):

Ammonium, NH4+, has a charge of 1+, so its O# is also 1.

OpenStudy (ipwnbunnies):

H has an O# of +1, and there's 4 of em like you noted, so the total H O# is 4+. O# of N will be +1 - 4 = -3

OpenStudy (anonymous):

OHHHHH so that + says that it's a charge of positive 1 so basically it goes with the H and cancels one out?

OpenStudy (anonymous):

wait i worded that bad

OpenStudy (anonymous):

so N has a charge of -4? i thought it had a -3 charge. waiittt so if it's just a postive charge. then it means just one? so whatver N equals, it's that charge?

OpenStudy (ipwnbunnies):

Oxidation numbers and ion charges don't have a connection. Ion charges exist, but oxidation numbers are made up to help us with redox reactions.

OpenStudy (ipwnbunnies):

Nitrogen usually has a -3 charge in ionic bonds.

OpenStudy (anonymous):

ah ok then

OpenStudy (ipwnbunnies):

I don't think you looked at this question right lol. O# of N + 4(O# of H) = -1

OpenStudy (ipwnbunnies):

Nitrogen doesn't have a -4 charge or a -4 O# in the ion. I used 1-4 because I was the subtracting the O# of the Hydrogen from the total O#.

OpenStudy (anonymous):

but howd you know the total?

OpenStudy (ipwnbunnies):

I mentioned it above. Ammonium, NH4+, is a polyatomic ion with a +1 charge. Polyatomic ions also have O#s that are the same as their ion charge. So, NH4+ has an O# of 1.

OpenStudy (anonymous):

okk thanks!

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