What is the electron structure of nitrogen? 1s22s22p3 1s22s23s22p1 1s32s32p1 1s12s12p5
SORRY I DONT KNOW THIS ONE BUT I DO BELIEVE THAT thomaster MIGHT! WOULD YOU LIKE ME TO ASK HIM????
yesssss please !!
OK I WILL!
Message me if he knows please :)
Actually you can ask him!! you are going to put in this sign @ and then type in his name so it will look like this @thomaster and then he can come and help you.
okay thanks !!
Helpp ahaa!! >.<
Thank YOOOOUU!!!
First you have to know how the system of electron configuration works. I'll post an image.
Now you got to know where nitrogen is in this version of the periodic table
Nitrogen is in group 15, top row. This is P-block 5A
You go from the left to the right. starting on the top left. this is 1S Then you go to the right, you'll find another 1s. Together this is \(\large\sf 1s^2\)
Thank you for helping I was interested in what the answer was to but was stuck on who to ask! :)
now we go 1 row down, starting on the left. you'll find the 2s row. we have 2 elements in this row as we go to the right, so we write down \(\sf\large 2s^2\) So we now have \(\sf\large 1s^22s^2\)
i Know the answer , just watching and learning now ;o
then continue to go to the right, we get to the 2p row. Nitrogen is the third element in this row. so we write \(\large\sf 2p^3\) the number before the s or p or d or f is the number of the row. the exponent is the number of elements you count until you get to the element you want, nitrogen in this case. So we now have \(\large\sf 1s^22s^22p^3\)
@math_genius123 stop talking nonsense please. you're not adding anything here, just ruining the learning process.
Have a look at this image for better understanding how it works
Still looking over this too Understand 100%
Now for another bonus example, we can take Arsenic and determine the electron configuration of that one. It works just the same, only the configuration will be a bit longer.
BONUS ^.^
Hai Sweet @Help713 , WeLcoMe to OpeN stuDy.. !! Wondering If you are satisfied with this answer, Please close this Question. Thank You ! Keep in touch with Open Study.. Bye !
Join our real-time social learning platform and learn together with your friends!