Mathematics
21 Online
OpenStudy (vshiroky):
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OpenStudy (vshiroky):
OpenStudy (vshiroky):
@ikram002p @calculusxy
OpenStudy (vshiroky):
Do I do this the same way?
OpenStudy (calculusxy):
Yes but now solve for c (hypotenuse).
OpenStudy (vshiroky):
c2=20
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OpenStudy (vshiroky):
so the first answer would be square root 20 and the second 4.47 again?
OpenStudy (calculusxy):
No this is different. I meant to use the same formula.
OpenStudy (ikram002p):
ur correct :D
OpenStudy (vshiroky):
I did use the same formula
OpenStudy (calculusxy):
Ok sorry I didn't solve the problem yet. But you are correct :)
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OpenStudy (calculusxy):
Remember to find the radical of 20 for the exact value of c.
OpenStudy (vshiroky):
isnt that what I did?
OpenStudy (calculusxy):
Yup. Just a short reminder! :)
OpenStudy (ikram002p):
nw , for approximation ,
type \(\Huge \sqrt 20\) also work ..
4.47 rounds to 4.5 hm
OpenStudy (calculusxy):
But we had to round two decimal places.
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OpenStudy (vshiroky):
the first blank is \[\sqrt{20}\]
OpenStudy (calculusxy):
So we didn't necessarily have to round @ikram002p
OpenStudy (vshiroky):
and 4.47 since it says round 2 decimal places as needed
OpenStudy (ikram002p):
yess vshiroky , the exact sol is sqrt 20 , and aproximation 4.47
OpenStudy (calculusxy):
Yes that's right @vshiroky