Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (vshiroky):

Help

OpenStudy (vshiroky):

OpenStudy (vshiroky):

@ikram002p @calculusxy

OpenStudy (vshiroky):

Do I do this the same way?

OpenStudy (calculusxy):

Yes but now solve for c (hypotenuse).

OpenStudy (vshiroky):

c2=20

OpenStudy (vshiroky):

so the first answer would be square root 20 and the second 4.47 again?

OpenStudy (calculusxy):

No this is different. I meant to use the same formula.

OpenStudy (ikram002p):

ur correct :D

OpenStudy (vshiroky):

I did use the same formula

OpenStudy (calculusxy):

Ok sorry I didn't solve the problem yet. But you are correct :)

OpenStudy (calculusxy):

Remember to find the radical of 20 for the exact value of c.

OpenStudy (vshiroky):

isnt that what I did?

OpenStudy (calculusxy):

Yup. Just a short reminder! :)

OpenStudy (ikram002p):

nw , for approximation , type \(\Huge \sqrt 20\) also work .. 4.47 rounds to 4.5 hm

OpenStudy (calculusxy):

But we had to round two decimal places.

OpenStudy (vshiroky):

the first blank is \[\sqrt{20}\]

OpenStudy (calculusxy):

So we didn't necessarily have to round @ikram002p

OpenStudy (vshiroky):

and 4.47 since it says round 2 decimal places as needed

OpenStudy (ikram002p):

yess vshiroky , the exact sol is sqrt 20 , and aproximation 4.47

OpenStudy (calculusxy):

Yes that's right @vshiroky

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!