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Mathematics 8 Online
OpenStudy (anonymous):

Cx+Gy=M x=

OpenStudy (ipwnbunnies):

Sweet. What's the first thing you think we should do?

OpenStudy (anonymous):

I don't know honestly

OpenStudy (mathmale):

the problem might be a little easier if you'd please include the instructions.

OpenStudy (solomonzelman):

isolate Cx and divide both sides by C

OpenStudy (solomonzelman):

( If I am understanding the problem correctly )

OpenStudy (anonymous):

solve. the solution to x=.@mathmale

OpenStudy (solomonzelman):

I told you how to do it.

OpenStudy (mathmale):

I'd like to see something like this: Given Cx+Gy=M, solve for x. Fine. Following Solomon's advice, how would you isolate Cx on the left side, with all other terms ending up on the right side?

OpenStudy (anonymous):

I don't know I got k/d-gy but its wrong

OpenStudy (solomonzelman):

You got KD ? Kevin Durant ?!?!

OpenStudy (anonymous):

no

OpenStudy (solomonzelman):

for your problem you just got to 1) Subtract Gy from both sides 2) Divide by C (I pretty much gave you a plain answer)

OpenStudy (mathmale):

Given Cx+Gy=M, please subtract Gy from both sides.

OpenStudy (solomonzelman):

Divide \(\color{blue}{ \sf both~~~~sides }\) by C.

OpenStudy (mathmale):

(same thing as solomon is asking you to do).

OpenStudy (mathmale):

@cmenendez55 : would you please type out your final expression for x?

OpenStudy (anonymous):

I already got it. its x=(k-gy)/d

OpenStudy (solomonzelman):

where do you get the "k" ? Let me recall the question please \(\color{blue}{ \sf Cx+Gy=M, ~~~~~x=? }\)

OpenStudy (mathmale):

Where'd that "d" come from?

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