the vertices of a triangle are p(-7 -4), q(-7 -8), and r (3 -3). Name the vertices of the image reflected across the line y=x
just flip the values of the x and y. so point p would be (-4, -7), q would be (-8, -7) and r would be (-3,3). The key to this solution would be to find that for any x value you plug in you get the same y value. However, you want it to be reflected across which means that you need to take the inverse of the function. Hope this helps!
Do you think you could help me with a few more?
yeah sure, but try to make it fast as I need to sleep please.
the vertices of a triangle are a(-6, -4), b(-3,5), and c(1,-1). Name the vertices of the image reflected across the x-axis.
and thank you!
When reflecting on the x-axis, the y-value would be negative as you are taking it down below. Therefore, to get all of these solutions you would need to take the opposite values of the y coordinate. This would make a (-6, 4) and b (-3,-5) and c(1,1)
If you are reflecting across the y-axis you would take the opposite of the x-value.
and you are more than welcome.
i have 2 more is that okay?
yupp lets get them! post them both please so I can tackle them all at once.
The vertices of a triangle are p(-2, -4), q(2,-5), and r (-1,-8). Name the vertices of the image reflected across the y-axis.
Take the opposite of the x-axis. so p(2, -4), q(-2,-5) and r would be (1,-8)
Find the image of O(-2,-1) after two refections, first across the line y=5, and then across the line x=1.
Give me a minute please, I took this so long ago.
oh no youre fine
I got it! To do this you will need to subtract the y = 5 from the x and the x=1 from y-value. This means that the x would be 5-(-2) = 7 and the x would be 1-(-1) = 2 so the point would be (7, 2)
Have an extremely good night and please don't forget to fan me!
D; that isnt an option...
what options do you have?
@abbi5169
are you there?
its okay i got it! thank you so much for helping
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