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Chemistry 4 Online
OpenStudy (anonymous):

write the balanced net ionic equation for the following mixture: NaNO3 + KI

OpenStudy (anonymous):

This is a double replacement reaction So we can say that the balanced original equation is: NaNO3 + KI ---> NaI + KNO3

OpenStudy (anonymous):

Do you know your solubility rules to determine which product is solid?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

We'll anything with NO3 or K is soluble. So we know that NaI is not soluble

OpenStudy (anonymous):

Can you expand the equation using only ions?

OpenStudy (anonymous):

im not sure

OpenStudy (anonymous):

Okay so I'm gonna use parenthesis to show separate ions (Na+) + (NO3-) + (K+) + (I-) ---> (K+) + (NO3-) + (KI)

OpenStudy (anonymous):

Now cancel any ions that are on both sides of the arrow. Those are called spectator ions. When you cancel we are left with.... (K+) + (I-) ----> (KI)

OpenStudy (anonymous):

That's the net ionic equation

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