Could someone explain how to do this problem?
Capacitors of 10mF and 20mF are connected in series, and this pair is then connected in parallel with a 30mF CAPACITOR. What is the equivalent capacitance of this arrangement?

Question

Could someone explain how to do this problem?
Capacitors of 10mF and 20mF are connected in series, and this pair is then connected in parallel with a 30mF CAPACITOR. What is the equivalent capacitance of this arrangement?

anonymous · Answer

just go to hyperphysics,  capacitor button. series parallel combination.  the formula is there.

anonymous · Answer

Is it (1/10)+(1/20)+(30)?

anonymous · Answer

For capacitance in series the formula is $$\frac{ 1 }{ Ceq } = \frac{ 1 }{ C _{1} } + \frac{ 1 }{ C _{2} } + . . . \frac{ 1 }{ C _{n} }$$ and for parallel it's simply $$Ceq = C _{1} + C _{2} +. . . C _{n}$$ so your equation would be $$C _{12}= \frac{ 1 }{ 10 } + \frac{ 1 }{ 20 } $$ then $$C _{12} + 30 mF$$ since in parallel

whpalmer4 · Answer

capacitors in series combine with the same formula as resistors in parallel.
capacitors in parallel combine with the same formula as resistors in series.