Help!!! A manufacturer has determined that the total cost C of producing Q units of a product is given by C=0.04Q^2+4Q+6400. AVERAGE cost will be a minimum at a production level of (a)100 units (b)200 Units (c)400 units (d)800 units (e)none of the above?

Question

lucaz · Answer

if you put the equation in the form a(x-h)+k, where (h,k) is the vertex, you can find the maximium or minimum value

lucaz · Answer

first factor 0.04 from 0.04q^2+4q:
0.04(q^2+100q)+6400

lucaz · Answer

(sorry, Im using a tablet)
then complete the square:
0.04(q^2+100q+2500)+6400-(0.04*2500)

lucaz · Answer

it becomes:
0.04(q+50)^2+6300 or 0.04(q-(-50))^2+6300
the vertex is (-50,6300)
but now it doesnt make sense for me, we can't have a negative production..  when q=-50 the equation gives the minimal value, 6300

lucaz · Answer

usually we solve these max/min value finding the vertex of the parabola..

anonymous · Answer

Which answer do you think is the closest?

lucaz · Answer

I think E, none of the above, but I'm not sure =/