Question

parametric equation of lines

Answer 1

1 sec

Answer 2

so if the y=x line is c1 and y=sqrt(x) is c2, i have

c1: (0,0) -> (1,1)
r(t) = (1-t)<0, 0> + t<1, 1>
=<t, t> 0<t<1

and

c2: (1,1) -> (0, 0)
r(t) = <t, sqrt(t)> 1<t<0

Answer 3

the <'s are supposed to be less than or equal to

Answer 4

is it possible to have 1<t<0 in c2 though?

Answer 5

The <'s and >'s aren't greater than or less than signs. It's just how to signify parametric equations.

Answer 6

oh

Answer 7

so it just signifies the direction?

Answer 8

Oh, there is greater and less than being used in this problem though. I didn't look at the problem. And the way the parametric equation graphs as t increases is the direction of the graph.

Answer 9

ah ok that makes sense. it is possible to have a greater value for the left value then? so, you could have 1<t<0?

Answer 10

Oh I see, for c2 it would be 1<t<0 I believe.
x: sqrt(t)
y: t

Answer 11

kk, yah that was what was throwing me off. wasn't sure if you could have a higher number that is less than

Answer 12

so another example

Answer 13

Yeah, it's tracing downward so it would be right.

Answer 14

so this would be <cost, sint> but it would be pi/2 < t< 0

Answer 15

Wrong picture lol.

Answer 16

?

Answer 17

The picture you gave me...Parametric eq. would be <t, 1-t^2> , 0<t<1

Answer 18

ah k nvm was thinking it was a circle

Answer 19

alright i think i got it thank you very much

Answer 20

@ksmith197 Hmm, it might be a circle. Problem is, we don't see the full graph plus the problem gave us the equation of the line.