Two stones are thrown vertically upward from the ground , one with 3 times the initial speed of the other. Assume free fall.
a) If the faster stone takes 12.0s to return to the ground, how long will take the slower stone to return??
b) if the slower stone reach a max height of H, how high (in term of H) will the faster stone go??

Question

Two stones are thrown vertically upward from the ground , one with 3 times the initial speed of the other. Assume free fall.
a) If the faster stone takes 12.0s to return to the ground, how long will take the slower stone to return??
b) if the slower stone reach a max height of H, how high (in term of H) will the faster stone go??

anonymous · Answer

Well since you dunno the velocity of the stone
Consider one stone has initial velocity v, and the other 3v .. !! that should get you going!

anonymous · Answer

So should I use a pro rata??

anonymous · Answer

Like this 12.0s/3v = x/v
And I find x as the time for the slower stone ?

anonymous · Answer

No what is that o.O
just use your kinematic equations of motion and do it will ya? o.>O

anonymous · Answer

Someone said that today :/ sorry!

anonymous · Answer

you should solve a problem using things that you understand.. not by just applying some formula.. which may or maynot work.. 
what is the point in using some formula and getting the answer which you don't even understand? :)
so use the nice old equations of motion.. and try to get the answer now.. !

anonymous · Answer

Okay I will try

anonymous · Answer

And what do I do about part b????