Question

General solution to differential equation dy/dx = xy^2?

Answer 1

where are you stuck?

Answer 2

This is what i have so far... is this right?
\[dy \frac{ 1 }{ y ^{2} } = x dx\]
\[\int\limits y ^{-2} dy = \int\limits x dx\]
\[\frac{ y ^{-1} }{ -1 } = \frac{ x ^{2} }{ 2 } + C\]
\[\frac{ 1 }{ y } = -\frac{ x ^{2} }{ x ^{2} } - C\]
\[y = \frac{ 2 }{ -x ^{2} } + C\]

Answer 3

Oh wait, there's a mistake in my equation

Answer 4

yep x^2/x^2

Answer 5

The second to last equation should be -x^2 / 2 - C

Answer 6

what about everything else, is my final answer wrong?

Answer 7

not exactly correct!

Answer 8

hmm.. please give me a clue!

Answer 9

when you are inverting the 1/y to y,,, on the right side you cannot invert x^2/2 + c
to 2/x^2 +C