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OpenStudy (anonymous):
how many atoms are in 1.4 mol of PF(3)
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OpenStudy (anonymous):
\[1.4 mole \times \frac{ 6.0223x10^{23} molecules PF _{3} }{mole } \times \frac{ 4 atoms }{ 1 molecule }\] =3.372x10^24 atoms
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