What torque must be applied to a wheel with a moment of inertia of 0.19 kg·m^2 to make it rotate at 11 rad/s in 10 s? a. 0.21 Nm c. 0.017 Nm b. 5.8 Nm d. 0.17 Nm
@kewlgeek555
\[F = ma\] this is newtons second law in linear motion similarly do you know what is newton's second law in Rotational motion?
Well, I have 3 questions left that I've attempted. but failed miserably. Just kinda lookin for an answer. so i can go back and check my work.
tel me what is your answer.. and ll check if its right :P
I got A.
now im doing a retake for my online course and it was wrong but now i don't see why?
that is right o.O .. although your question is poorly worded m assuming that the wheel is initially at rest, and it is required to get it up to a speed of 11 rads/second in 10 seconds.. in that case, required angular acceleration is 1.1 rads/sec^2 and the required torque= 1.1 times 0.19 = 0.209 Nm
@Mashy This online class is ridiculous. even some questions that i got that should be right. Aren't. It's somewhat of a mess XD But thank you very much, mind helping me with another?
sure!
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