Freddie is at chess practice waiting on his opponent's next move. He notices that the 4-inch-long minute hand is rotating around the clock and marking off time like degrees on a unit circle. Part 1: How many radians does the minute hand move from 3:35 to 3:55? (Hint: Find the number of degrees per minute first.) Part 2: How far does the tip of the minute hand travel during that time? Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches? Part 4: What is the coordinate point associated with this radian measure? @mathmale
First, woohoo, how many minutes are there in one hour?
60minutes
hello
Right. And how many minutes are there between 3:35 and 3:55, when we're reading time?
20mins
Right. so, the time period from 3:35 to 3:55 is what fraction of an hour?
uhh1/3
Good. and one full circle, measured in radians, is 2pi radians. What is 1/3 of 2pi rad?
idk
@mathmale
Just write\[\frac{ 2\pi }{ 3 }\], followed by the units of measurement (radians). The time span 3:35-3:55 is represented by a central angle of 2pi/3 radians.
2.093333
summary: 1. Find the number of minutes between 3:35 and 3:55. 2. Divide that by 60 minutes to obtain the fraction of a full circle represented by that time period. 3. Multiply the resulting faction by 2pi, to obtain the number of radians represented. You could type the answer as 2.093, or (better) leave it as 2Pi/3 radians.
For the next part of this problem, write out the formula for arc length in terms of the radius and the central angle.
thats for part one right
The central angle is 2pi/3; that's the answer to Part One. We need to move on to Part Two. Can you write out the formula for arc length?
hold up
i dont know it
Strongly suggest that you always look up words you don't know. I did a quick Internet search for "arc length formula" and found the following: http://www.mathsisfun.com/definitions/arc-length.html Arc length is most often represented by the letter " s ": s = r (theta), where s= arc length r = the radius of the circle theta = the central angle (we've already found this angle; it's 2pi/3)
i had a question for part one we were converting degress to radians right?
Unfortunately, Part B does not tell you that it's "arc length" that we're looking for. Instead, it asks how far the tip of the minute hand moves (in the arc from 3:35 to 3:55).
so we have part 2 already?
To answer your question about Part A: I asked you to multiply the radian representation of one full circle (2Pi) by 1/3 (which represents 20 minutes). So we were already dealing in radians and did not have to convert from degrees to radians.
For the purpose of review: Type out the formula for arc length here:
\[\theta*4\]
OK. I was hoping for \[s=r*\theta\]
oh ok so now what do we do
but what you have written would be ok, so long as you include the units of measurement of the radius. \[s=(central.\angle) * (radius)\]
Can you now find the arc length, s, using this formula? Go back and obtain the central angle and the radius, using appropriate units of measurement.
i dont know what to putor plug in
20 mins is the arc but i dont know whats the radius
what is the central angle (theta)? Just review our discussion, above; all the info you need is there. Regarding the radius: Look at the original question: what is the length of the clock's minute hand?
Review: \[s=r*\theta\] where theta is the central angle in radians (not degrees) and r is the radius of the circle in question. What is theta? What is the radius?
theta=2pi/3 radius=?
The length of the minute had is 4 inches; that's your radius. We want to know how far the TIP of the minute hand travels in an arc/circle as it moves from 3:35 to 3:55.
So theta= 2pi/3 (radians) and r = radius = ?
it had to travel 20 minutes
radius =4
It was in motion for 20 minutes, but it also traced out a distance. What was that distance? sorry to continue to be picky, but we must include units of measurement with every measurement. Thus, the radius is 4 inches. the central angle is 2pi/3 radians. Therefore, using \[s=r*\theta\] the arc length (the distance traveled by the tip of the minute hand) is what?
8.3732
I haven't actually tried the calculation. What I'd most like to see would look like this: distance traveled = arc length = (radius)*(central angle) = ( ? )* ( ? ) Please fill in the blanks.
4*2pi/3
@mathmale
I'm not going to abandon you. If I don't respond immediately, it means either that OpenStudy is slow or down or that I had something else to do while waiting for your response. Please label your result: arc length = distance traveled = 8Pi/3 inches.
Part C. Please type in the formula for arc length. (Repetition does help us learn and remember things like this.)
why would it be 8 pi
2*4=8, right?
yeah ok gotcha
Part C. Please type in the formula for arc length. (Repetition does help us learn and remember things like this.)
ok \[s=\theta*4\]
In Part C you are given the distance traveled and need to find the central angle. Please solve that arc length formula for the central angle.
hold the phone Math male what do i pput for part2 ?
@mathmale
You tell me. What does Part B / Part 2 ask you for?
so thats all i write for part 2? 4*2pi/3
As before, please label your answers and please include the appropriate units of measurement. In Part 2 we were supposed to do what? Have you seen the image I just uploaded?
@mathmale i know im annoying soo pls jst bare and im sorry
distanced traveled = "20" arc length = radius *central angle
all of what we're discussing now we'd discussed earlier, so I'd hope you'd go back and review that material. In Part 2 we're supposed to find the distance that the tip of the minute hand travels. That's arc length. Please write your answer with a label, in simplified form, with units of measurement: Distance traveled by tip of minute hand = S = arc length = ???
is 4 =arc length
@mathmale
\[s=r*\theta\] represents arc length; theta is the central angle (in radians) and r is the radius of the circle along which the tip of the minute hand travels. So, no, 4 is not the arc length. Try again. Solve s = r*theta for theta.
but you said earlier that its 4 inches the radius
Divde both sides of \[s=r*\theta\] by r, to solve for theta.
Yes, but you were asking me whether 4 is the arc length. (See your comment, above.)
4=radius and 2pi/3 = arc length
@mathmale
@mathmale you there??
That's a bit better: 4 inches is the radius, BUT 2pi/3 is the central angle. Would you please copy down this formula and note what each letter represents:\[s=r*\theta\]
can you pls jst tell me because this has been a drag
I'd like for you to have something to review, because we're going over the same thing repeatedly and losing time that way. Please define for me: s: r: theta:
Please start taking notes, so you have something to refer to. You will need this formula s=r*theta again and again.
s is length r is 4 theta is 2.093
the formula for arc length is \[s=r*\theta\] If we divide both sides by r, we get a formula for theta, the central angle:\[\frac{ s }{ r }=\theta\] This is the formula you need to answer Part 3. In this last formula, let s=arc length = 3pi inches, and let r=radius=4 inches. Determine theta, the central angle.
2.355
is theta
@mathmale
Yes, and that's the central angle, and the answer to Part 3. I really do expect you to learn these formulas and to know what each letter (s, r, theta) represents. Let's move on to Part 4.
You tell me, in your own words, what y ou think Part 4 calls for.
ok
its asking what point is is in this radian range? idk
It's asking for the coordinates of the tip of the minute hand when the central angle is 2.355 radians and the radius is 4 inches. (2,4) is a point in cartesian coordinates; it means that x=2 and y=4. In Part 4 we're dealing with polar coordinates, so instead of x and y, we use r (radius) and theta (central angle). What experience have you had so far with polar coordinates?
none
Please stop tagging me. I explained earlier that I will not abandon you. Many of the delays in my responses stem from OpenStudy's being overloaded and thus very slow. How do you normally learn new material? It would be grossly unfair if you were asked to find a point in polar coordinates without having had any introduction to polar coordinates. Do you have a textbook? Is there material in your online materials about polar coordinates?
If, in Part 3, the central angle is (3pi/4) radians (you typed 2.355 radians), and the radius is 4 inches, then the coordinates of the point in question in Part 4 is just (4 inches, 3pi/4 rad). Coordinates of a point in polar coordinates are (r, theta), where r= radius and theta=central angle. Can you find this information in your textbook or in your online materials?
mathmale are you recieving the messages im sending you?
In review: Part 1: That 20-minute time change is represented by (20/60)*2Pi radians, or 2Pi/3 rad. Part 2:
Yes, I've received many of your private messages and believe I'm receiving your messages in this chat.
then pls reply
Part 1: That 20-minute time change is represented by (20/60)*2Pi radians, or 2Pi/3 rad. Part 2: during that 20-minute interval, the tip of the minute hand travels s = r*theta inches, or s = (4 inches)(2pi/3 rad). Please stop tagging me. I explained earlier that I will not abandon you. Many of the delays in my responses stem from OpenStudy's being overloaded and thus very slow. How do you normally learn new material? It would be grossly unfair if you were asked to find a point in polar coordinates without having had any introduction to polar coordinates. Do you have a textbook? Is there material in your online materials about polar coordinates? Do you want to tackle that new problem you've posted, or do you want to finish this current problem?
@mathmale I would like to know how to find the coordinates.
@mathmale. part 4 please!
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