Question

Big test coming up! Need help with 16 Geometry Problems! :) Please help.
~In Dire Need of Help

Answer 1

geometry...that's all about rocks and volcanos an stuff...yeah?

Answer 2

First seven questions...

Answer 3

Geometry is the study of shapes

Answer 4

jks, sorry ;P

Answer 5

Q1: volume = area of base x ht

Answer 6

shape 1 base = rectangle
formula for area of rectangle =...? @djibben615 ?

Answer 7

yep. I got question number 1. I need help with rest :)

Answer 8

@mathmale @amistre64

Answer 9

Go right ahead. Make your own choice of answer and explain your reasoning.

Answer 10

Q5 - volume of sphere = \[ \large \frac 43 \pi r^3\] and \[\large r = d/2\]
so how does change in d affect change in V ?

Answer 11

hint... 18:24 = 3:4 ratio in diameters

Answer 12

ah. ok.
do I do R=d/2 twice for both snowballs?

Answer 13

So it is 8 times bigger?????

Answer 14

q4: vol of cylinfer = area of base x ht
= pi r ^2 x ht

cyl 1
= pi r ^2 x ht
= pi 1^2 x 10
= 10pi inches sqrd or volume

cyl 2
10pi= pi r ^2 x ht
10pi= pi 2^2 x ht
10 = 4x ht
ht = 10/4

Answer 15

q3... i dont know jack about imperial measurements... whats an ounce?

Answer 16

Q3 volume of barrel = area of base x ht
= pi r ^2 x ht
= pi 4.25^2 x 11
= 624.195 cubic inches

Answer 17

is 8 ounces a gallon?

Answer 18

um...no its not

Answer 19

q6: 2 long, 4 wide, 6 high
vol of single box = xyz
vol of shrink wrap = 2x*4y*6z = xyz*48
so 48 times the volume

Answer 20

what's the relationship of gallons to OZ then, as we use litres down here?

Answer 21

q7... no idea what that is, sorry

Answer 22

back to q 1... u know the rule for area of a hexagon...?

Answer 23

128 ounces in one gallon

Answer 24

ahh, cool... how many cubic inches in a gallon?

Answer 25

not sure.

Answer 26

Could we start at question 2? I still never got the answer completely. How many times bigger was it again?

Answer 27

apparently its 231... so lets go with that
\[\large 624.195in^3 \times \frac {1 gal}{231in^3} \times \frac{128 oz}{1 gal} \times \frac {1 cup}{8oz} = ?\]

Answer 28

\[\large =\frac{79896.96}{1848} = 43.24 cups\]

Answer 29

Q2.. sure

Answer 30

vol of snowball 1
vol of sphere = 4/3 pi r ^3
r = diameter/2 = 18/2 = 9
so
vol of sphere = 4/3 pi r ^3
vol of sphere = 4/3 pi 9 ^3
vol of sphere = 3053.63 (or 972pi)

vol of snowball 2
vol of sphere = 4/3 pi r ^3
r = diameter/2 = 24/2 = 12
so
vol of sphere = 4/3 pi r ^3
vol of sphere = 4/3 pi 12 ^3
vol of sphere = 7238.23 (or 2304pi)

ratio volume 1 to volume 2
= 972 : 2304
= 27 to 64

ratio radius 1 to radius 2
= 9 : 12

so \[\large \frac 9{12} \times x = \frac {27}{64}\]
therefore x = 2/3

Answer 31

but that's only comparing radius to volume
\[\large \frac 9{12} \times x = \frac {27}{64}\]
\[\large \frac {d1}{d2} \times x = \frac {27}{64}\]
\[\large \frac {18}{24} \times x = \frac {27}{64}\]
\[\large x = \frac {9}{16}\]

Answer 32

So....the answer is 0.6?

Answer 33

so 18/24 = 3/4
we started with a 3 : 4 ratio of diameter of snowball 1 to diameter of snowball 2
now we multiply by 9 to 16 ratio to get the volume
9 to 16 ratio = (3/4)^2
so 3/4 x 3/4 x 3/4 = 27/64
so relationship between volume and diameter is ratio of diameters...cubed (to power of 3)

Answer 34

So its 0.5?

Answer 35

think about it this way:
first snowball = 3cm across
2nd snowball = 15 cm across

ratio of length 1 to length 2 = 3: 15 = 1 : 5... new snowball is 5 times the length of old

therefore if ratio of new to old is 5: 1 for diameters, ratio of volumes should be 5^3 to 1
so 5x5x5 = 125 x times volume

Answer 36

proof: vol of snowball 1 = 36pi
vol of snowball 2 = 4500pi
36 : 4500 = 1 : 125 = 125 times the size = 5^3 times the size

Answer 37

no, not .6 or .5
find ratio of lengths
cube that ratio
= ratio of volumes

Answer 38

it says to round to the nearest tenth...

Answer 39

ok, then ratio = 4 to 3
(4/3 cubed) = 64/27 = 2.37 times more volume = 2.4 (rounded)

Answer 40

so arnies snowball is 2.4 times the volume of robertos snowball

Answer 41

AH gotcha!

Answer 42

sweeeet :)

Answer 43

so type back yes or no if u got them down:
1a?

Answer 44

can we do number #2?

Answer 45

So I have numbers 1, 3, 4, & 5 done. If we finish number 2, we can move on to the last 8 problems.

Answer 46

area of a hexagon = (3 x sqrt 3 )/ 2 times side sqrd

Answer 47

\[\Large Area = \frac {3 \times \sqrt 3}{ 2} \times s^2\]

Answer 48

volume = area of base x ht
u can calculate from here?

Answer 49

um....I may need some assistance. What does the s stand for again in your equation?

Answer 50

side, so the side length of one of the sides of the hexagon

Answer 51

ah sorry. I really am not this dumb...just struggle with this chapter.

Answer 52

all good, dumb ppl dont ask questions, so ur a step ahead of the rest in my view

Answer 53

thanks! :)
So, how do I find the side length? I can calculate the equation but not sure how to find the side length.

Answer 54

side length should be given... in this case it's 8

Answer 55

oH! I feel really stupid. I didn't notice the base was the same length. :)

Answer 56

hall good, chill hey ;)

Answer 57

\[Area = 3 \times \sqrt{3} \div 2 \times 8^{2}\]

Is this correct? And this will give me my answer?

Answer 58

that will only give u the areaa of the base... to get volume u need to times it by how long/heigh it it

Answer 59

So 166.28? That's my answer for the equation. Now what is the next equation?

Answer 60

I just multiply 166.28 x 8 x 20??