Question

Convert 0.575% (w/w) CuSO4 5H2O to %(w/v)

Density of 0.575%(w/w) is 1.67g/mL

Molar mass = 249.7g/mol

Answer 1

we have to find 1st of all the volume.
0.575% (w/w) meant
0.575 g of Cuso4.5h2O are dissolved in 100 gram of sample.
density = mass / volume OR volume = mass / density so,
vol = 100 / 1.67 = 59.88 mL
its mean 0.575 g of solute is dissolved in 59.88 mL, so %age will be:
w/V% = 0.575 / 59.88 X 100 = 0.96 % (w/V)