Question

Anyone in Connections taking algebra 2 B?

Answer 1

Need help with the get the picture portfolio

Answer 2

yes

Answer 3

do you have the get the picture portfolio done?

Answer 4

dno

Answer 5

https://www.connexus.com/content/media/621504-1132012-110216-AM-1919289153.pdf

Answer 6

did you do this?

Answer 7

i can't open i

Answer 8

I am in Connections, but not in so called course.

I would suggest asking a question directly, unless this is a classmate search - which is more appropriate for a Feedback section.

Answer 9

srry nvm

Answer 10

@doc.brown pls tell me your in connections?

Answer 11

Just write the question down, I will help.

Answer 12

• Measure the lengths of the arrows shown at the right.
What is the relationship between these lengths? How
does this relate to your research on perspective?
• Trace the four arrows at the right, moving the paper to the
left after tracing the longest arrow so that it is further away
from the others than it is now. What do you notice?
• Make a simple drawing of three or more similar objects
whose lengths can be represented by an arithmetic
sequence. Write the corresponding arithmetic sequence,
and a recursive or explicit formula for that sequence.

Answer 13

the firs arrow is 2in, the 2nd one is 1 1/2, the 3rd is 1 1/4, and the forth is 1 in

Answer 14

\[a_1=2\]\[a_2=1\frac{1}{2}\]\[a_3=1\frac{1}{4}\]\[a_4=1\]

Answer 15

if it says that im not here, it's because of the lag lol sorry

Answer 16

\[a_1=2\]\[a_2=1\frac{1}{2}=\frac{3}{2}\]\[a_3=1\frac{1}{4}=\frac{5}{4}\]\[a_4=1\]

Answer 17

\[a_1=2=\frac{8}{4}\]\[a_2=1\frac{1}{2}=\frac{3}{2}=\frac{6}{4}\]\[a_3=1\frac{1}{4}=\frac{5}{4}\]\[a_4=1=\frac{4}{4}\]

Answer 18

See the relationship now?
4:5:6:8

Answer 19

Yes!

Answer 20

I imagine the arrows are in a 3D landscape, you teacher is likely looking for a small rant about how things further away appear smaller, depending on your point of view? I don't know your research.

Answer 21

okay i was going to say that for the second part

Answer 22

now the third part has me at a lost

Answer 23

this is the picture i want to use

Answer 24

Just make up some number, like 2 or 3/7 or something.
Draw one length 1 and another some multiple of your made up number. 2x or 3x/7

Answer 25

Ok, you add three to each pile. Recursive. n+3

Answer 26

\[a_1=2\]\[a_n=a_{n-1}+3\]

Answer 27

okay so my arithmetic sequence would be 2:5:8:11:14 etc. and the recursive is what you just wrote?

Answer 28

Yup, double check to make sure what I wrote makes sense.
start with \(a_1\), which is 2
then make \(n=2\)
\(a_2=a_1+3=5\)\[a_3=a_2+3=8\]

Answer 29

keep going for n=3, n=4, n=5, etc

Look good?

Answer 30

yup thanks! can you help with another one?

Answer 31

file:///C:/Users/jennaci4/Pictures/621504-1132012-110216-AM-1919289153.pdf

Answer 32

Sure, if I get a medal here, best response button.
Then close the question and post a new one. I'll come find you.

Answer 33

okay thanks ill tag you!