Question

Solve the system algebraically. Check your work.

5x + 2y = 10
3x + 2y = 6

Make sure there are NO SPACES in your answer. Be sure to include a comma.

Answer 1

I don't get this question at all...

Answer 2

5x + 2y = 10
3x + 2y = 6 ---->(-1)
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5x + 2y = 10
-3x - 2y = -6 (result of multiplying by -1)
-------------add
2x = 4 -- divide by 2
x = 2
Sub in 2 for x in either equation to find y
5x + 2y = 10
5(2) + 2y = 10
10 + 2y = 10
2y = 10 - 10
2y = 0
y = 0

check..
3x + 2y = 6
3(2) + 2(0) = 6
6 + 0 = 6
6 = 6 (correct)

solution : (2,0)

Answer 3

Thank you very much! you explained it very well

Answer 4

your welcome. This can also be solved by using the substitution method. The reason I didn't use that way was because I do not like dealing with fractions

Answer 5

You can do substitution on this without doing fractions.

\[5x + 2y = 10\]\[
3x + 2y = 6 \]We have \(2y\) in both equations, so solve one for \(2y\) and substitute:
\[5x+2y=10\]\[2y=10-5x\]\[3x+(10-5x) = 6\]\[-2x+10=6\]\[-2x=-4\]\[x=-2\]etc.

Answer 6

sorry, obviously that should be \[x = 2\]!