a playing field is a rectangle that is 800 feet long by 180 feet wide. find to the nearest foot the length of a straight-line run that started at one corner and went diagonally to end at the opposite corner

Question

anonymous · Answer

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Can u see how this diagram describes the situation you are trying to solve? you are trying to find x

are you familiar with Pythagoras' Theorem?

anonymous · Answer

no lol im stuck and absolutly cant find the answer

anonymous · Answer

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This is the field, 800 long and 180 wide, and the diagonal line is the "straight line run" in the question that you are trying to find the length of

So to find the length of the run we have to find the length of the diagonal line, 

Now the diagonal line, as well as the top and right edges of the field form a right angle triangle, with the diagonal line being the hypotenuse

So we have a right angle triangle, with height 180, and length 800, and we want the length of the hypotenuse
 
Pythagoras' Theorem tell us that $$a^{2} + b^{2} = c^{2}$$

Where a is the height, b is the length, and c is the length of the hypotenuse.

Does this make it any clearer to you?

anonymous · Answer

oh a little maybe??? so i take 800 times 2 plus 180 times two?

anonymous · Answer

Close, but its not times 2, $$a^{2}$$ mean a squared, ie. a x a

so since $$a^{2} + b^{2} = c^{2}$$

if we take 180 squared + 800 squared, we will have the square of the length of the run, so you just have to find the square root of that to egt your answer

anonymous · Answer

so it would be 980??

anonymous · Answer

im stuck on this one bad