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Mathematics 14 Online
OpenStudy (anonymous):

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OpenStudy (accessdenied):

Have you made any attempts on this so far? Or just lost?

OpenStudy (anonymous):

I'm lost. O: I'm confused on how to form the equation

OpenStudy (accessdenied):

Hm... I have two ideas. One way seems like it would take quite a bit of work, would just be converting to rectangular coordinates and then using distance formula. That sounds ew to me because of a lot of steps The other is, for the most part, using Law of Cosines. Either of these seem good to you? :)

OpenStudy (accessdenied):

OpenStudy... ;~; I am assuming by "form the equation" we are heading towards the Law of Cosines route \( c^2 = a^2 + b^2 - 2ab \ \cos C \) The way it works is by drawing the two points, their segments with the origin and between each other, you create a triangle. The most catching part might just be the angle. But if you sketched this situation out, you might get a hint at the set-up.

OpenStudy (accessdenied):

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