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If 55.6 grams of butane reacts with excess oxygen, how many grams of carbon dioxide are produced?
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First, you begin by writing down the chemical equation. This is more commonly known as a \(\sf \color{red}{combustion~reaction}\).
Combustion follows this: \(\sf \color{blue}{C_nH_m + O_2 \rightarrow CO_2 + H_2O}\), which is essentilly saying, some organic molecule exposed to oxygen and some sort of energy, i.e fire, reacts to form carbon dioxide and water, gas.
Second step is to balance the equation. now, butane has the formula: \(\sf \color{purple}{C_4H_{10}}\)
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