A card is drawn from a well-shuffled standard deck of 52 cards. a) what is the probability that it is a spade? b) Probability that it is a king? c) Probability that it is a king of spades? are the events in part a and b independent?
a) 1/4 or 25% b) 4/52 or about 7.6% c) 1/52 or 1.9% they are independent
Almost had it typed out, but yes.
@DanielLions do you understand the answers that @ayubie gave?
@SpoonyBard Idk anything about cards, so no.
There are 13 cards for each of the four suits. So, 13 out of the 52 are either spades, clubs, hearts, or diamonds. 13/52 is simplified to 1/4 There are only 4 kings because there is one king for each suit. 4/52 of the cards are kings. There are only 4 kings, and only one of those kings are spades, so there is only 1/52
Do you understand now?
I think we should show how we know them to be independent also @OrangeMaster
@OrangeMaster yes and @SpoonyBard please.
do you know the definition of independence in probability?
yes @SpoonyBard
ok, then we can use bayes' rule to see if it fits the definition. Let \(P(S)\) be the probability of drawing a spade, and \(P(K)\) be the probability of drawing a king\[P(S\cap K)=P(S)P(K|S)\]we already have \(P(S)\), can you figure out the probability of drawing a king given that it is a spade?, i.e. \(P(K|S)\)
sorry, not bayes' rule, the multiplication rule*
or, as an equivalent question on an intuitive level, does knowing the suit tell us anything about the odds of drawing a king?
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