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if sect= -5 and terminal point for t is in quadratic 2 find sin^2t+cos^2t
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Do they want us to work this out the long way? Or can we simply make use of our most basic trig identity?\[\Large\bf\sf \sin^2t+\cos^2t\quad=\quad 1\]
it just says to find sin^2t+cos^2t
Ok fine we'll do it the long way ^^
which ever way makes more sense so I can understand it :)
We can relate secant back to cosine using our identity,\[\Large\bf\sf \sec t\quad=\quad \frac{1}{\cos t}\] So if,\[\Large\bf\sf \sec t\quad=\quad -5\]It implies,\[\Large\bf\sf \cos t\quad=\quad -\frac{1}{5}\]That make sense so far? :o
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ya
We're going to use this information to draw a triangle in the `second quadrant`. Because that's where they told us we're located.
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