The minimum number of cards to be dealt from an arbitrary shuffled deck of 52 cards to guarantee that 3 cards are from the same suit are?

Question

The minimum  number of cards to be dealt from an arbitrary shuffled deck of 52 cards to guarantee that 3 cards are from the same suit are?

akashdeepdeb · Answer

Here they want us to calculate the possible combinations of getting 3 cards from the same suit.
1 suit has 13 cards.
So you want to select 3 cards from any set of the 4 sets (hearts, clubs, spades, diamonds) containing 13 cards each.

As you have to make a selection of 3 cards from 13 cards.
The answer would be, $${^{13}C_3}$$

akashdeepdeb · Answer

Actually, my bad!
As there are 4 such suits, there is a possibility that you may get it from either of the 4 sets of 13 cards. So the final answer would actually be: $$^{13}C_3 + ^{13}C_3 + ^{13}C_3 + ^{13}C_3 ~~or~~ 4 * ^{13}C_3$$

Getting this? :)

anonymous · Answer

what i can see is 
So the final answer would actually be: $$^{13}C_3 + ^{13}C_3 + ^{13}C_3 + ^{13}C_3 ~~or~~ 4 * ^{13}C_3$$

anonymous · Answer

i think it's not showing up the correct format of wht u wanna convey here !

akashdeepdeb · Answer

There must be a problem with the website now. I am not being able to copy and paste anything here too. Let me message you the answer, hold on.

anonymous · Answer

thank you :)

ganeshie8 · Answer

best case 3, worst case 9
so answer should be 9

akashdeepdeb · Answer

Yeah, I corrected that for @moli1993 thanks, @ganeshie8 ! :D