need somebody to double check my work
\[\frac{ 3x-4 }{ 5}\]
@whpalmer4
what work... tell me...
i thought you was suppose to multiple 5 with the equation
you need to find the value of "x".....? or what
yea
well x=4
3x-4/5=0 3x-4=0 3x=4 x=4/3
f(4)=3x-4 over 5
f(4)=3*4-4 f(4)=12-4 f(4)=8
but what happens to the 5
just insert 5 in f(x)
im lost now
ahhh...ok see f(5)=3*5-4 f(5)=15-4 f(5)=11
i didnt think you was suppose to that cause f(x)=f(4) already
no dear... we had already 5 there too
but in the question there are 3 different equation and two equation has the same solution
the first equation i had got 8 and the other one i got 9 so this equation final answer should be 8
@handyandy3 @CGGURUMANJUNATH @Kilorion @whatyouknowboutdat @yoletstalk @TuringTest
The problem as you've posted it here is incomplete. Can you tell us exactly what the original problem says, or post a screenshot or photo?
Which of the following statements have the same result? Explain each step in solving each one. f(3) when f(x) = 2x + 2 f-1(4) when f(x) = 3x minus 4, all over 5 y + 10 = 2y + 1
i hope that kind of help i had already figured out the first equation and the third equation i just cant seem to figure out the second equation
Okay. That's much better! \[f(x) = 2x+2\]\[f(3) = 2(3)+2 = 8\] \[y + 10 = 2y + 1\]\[10 = y + 1\]\[y = 9\]
ok i did that 1 already and i did the first one as well i need help with the second one
\[f(x) = \frac{3x-4}5\]To find \(f^{-1}(x)\) we swap the variables and solve for \(x\) \[y = \frac{3x-4}{5}\]swap variables: \[x = \frac{3y-4}{5}\]Solve for \(y\) \[5x = 3y-4\]\[5x+4 = 3y\]\[y=\frac{5x+4}{3}\]\[f^{-1}(x) = \frac{5x+4}{3}\] Now you plug in the desired value of \(x\) and evaluate the result.
ok so 5*4=20 20+4=24 24/3=8 omg thank you so much for helping me:))))
You're welcome!
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