Question

How to add

Answer 1

I need to add this problem

Answer 2

ok, what problem?

Answer 3

and this
The perimeter of a paved area being built at a playground is going to be 46 meters. If the length and width are each a whole number of meters, what should the length and width of the area be to cover the greatest possible area? Draw a picture and make an organized list to solve.

Answer 4

\[\frac{ 51 }{ 4 } + \frac{ 32 }{ 4 }\]

Answer 5

NOPE

Answer 6

It's 5 and 1/4 and 3 and 2/4

Answer 7

ok got it

Answer 8

Do i keep that d. the same or change it??

Answer 9

@California_Babe : Please post only one question at a time.

5 1/4 and 3 2/4 are "mixed numbers;" they are part integer and part fraction.

There are at least two ways to do this:

1) Add the integer parts separately; add the fractional parts separately; add the two results together.

2) Convert both 5 1/4 and 3 2/4 to improper fractions: 21/4 and 14/4; add these, and then express the result as another mixed number.

Your choice! Please show your work.

Answer 10

You have the same denominator in both fractions, so by all means keep it.

Answer 11

7 3/4????

Answer 12

good work mathmale
for the other problem you must make a function of the area
A = x * y
f(x) = A , x= length, y=width
then you have to find the relation, you can set it from the perimeter
46 = (x+y) * 2
23 = x + y
x = 23-y
substitute in the function
A = (23-y) * y
A = 23y - y^2
then find the derivative
\[A \prime =23 - 2y\]
\[A \prime =0\]
0 = 23 - 2y
2y = 23
y = (23)/2
then x = 23 - (23)/2 = (23)/2

Answer 13

THX!!

Answer 14

u r welcome