Find the average rate of change for the given function from x = -1 to x = 5.
@texaschic101
@sourwing
@kc_kennylau Do you know how to do this?
The average rate of change from point a to point b, is just the value of the function at point b - the value at point a, divided by the quantity (b-a).
So what do I divide?
Say you have a function \(f(x) = 3x+2\) (I'm not looking at your document — I don't open files that I have to download from unknown people) To find the average rate of change of \(f(x)\) between \(x = a\) and \(x = b\), you evaluate this: \[m = \frac{f(b)-f(a)}{b-a}\] That gives you the slope of a line which connects the value of the function at points \(x = a\) and \(x = b\). That slope is the average rate of change, because that's what slope is!
Since you won't open the table the table says: x y -1 7 3 3 5 1
And its saying to "Find the average rate of change for the given function from x = -1 to x = 5."
So what numbers do i plug in..
\(y = f(x)\) so your table could just as well be labeled \[x\qquad f(x)\]
Find the value -1 in the x column, and find the value in the y column in the same row. Those are \(a\) and \(f(a)\) respectively. Now find the value 5 in the x column, and the value in the y column of that row. Those are \(b\) and \(f(b)\) respectively. Plug the 4 numbers into the formula. What do you get?
For giggles, we'll do the problem again with a formula: \(y = -x+6\) but let's get your answer to this first.
Still have no idea where to plug in what you're telling me to. :I I'm a really visual person :I so...I don't know where to plug in -1 but the y value next to it is 7. Still have no clue where to plug in 5 but the y value next to that is 1.
Would it be 7(-1)-5(1)/-1-5
Which would come to -12/-6 then reduce to 2 but that's not an option so where'd I go wrong
You're getting close! Here's the table x f(x) ----------- -1 7 3 3 5 1 We want to find the average rate of change of f(x) (aka "the function") between x = -1 and x = 5. We evaluate the function (read: look up the value in the table) at x=a=-1: x = -1, f(-1) = 7 We evaluate the function at x = b = 5 x = 5, f(5) = 1 any question about that so far?
Okay understood
Now what
The starting point is (-1,7), or in my terminology, \((a, f(a))\) The ending point is (5,1) or in my terminology, \((b, f(b))\) We need to plug those into this formula: \[m = \frac{f(b)-f(a)}{b-a}\]
That's what I thought I did but I clearly did it wrong
Try again. You put in a bunch of extra numbers. Very carefully match up the items I identified and write the formula
Here, I'll take you through it step by step: What is \(a=\)
1?
Or no
I don't know
I told you the value in several different places...it is the x value for the starting point. We are finding the rate of change from x = -1 to x = 5.
I wrote a minute or so ago "The starting point is (-1,7), or in my terminology, \((a,f(a))\)" Match them up!
(-1,7) (a, f(a))
Yeah sorry I have no clue I completely give up. Haha I'll just skip this question I don't have any more time
Thanks for trying to help though I guess
No, don't give up.
If I tell you there are two numbers, in order, (a,f(a)) and those two numbers are (-1,7), are you telling me you can't figure out the value of a?
I don't have time sorry I said -1 and you said no so
No, you said 1!
Oh my god -1 okay whatever
Typo
It makes a difference!
Ok
\[m=\frac{7-1}{5-(-1)}=\]
1
Cause 7-1=6 and 5-(-1) = +6
So 1.
That's right, but this time I made the mistake :-) \[m = \frac{1-7}{5-(-1)}=\]
-6/6 = -1
There we go!
Here's a picture of what we did:
(-1,7) is the starting point, or (a,f(a)), way up in upper left corner. (5,1) is the ending point, or (b,f(b)), bottom right corner
Here the points are joined and I put on grid lines to make it easy to see that for each step to the right along the x-axis, the y value goes down by 1. That's a slope of -1/1 = -1, just like we found.
If we'd wanted to find the average rate of change between another two points, say (1,5) and (3,3), \[m = \frac{3-5}{3-1} = \frac{-2}{2} = -1\]Always will be the same if we are finding the average rate of change along a straight line like this
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