need help with this question giving medal
When solving a radical equation, Beth and Kelly came to two different conclusions. Beth found a solution, while Kelly's solution did not work in the equation. Create and justify two situations: one situation where Beth is correct and a separate situation where Kelly is correct.
@phi @whpalmer4
If you have an equation with a square root on one side, but not the other, and you have to square both sides to solve the equation, you will often introduce what is called an extraneous solution, which is one that solves the new equation (after squaring) but does not work in the original. This video covers it pretty well, I think: https://www.khanacademy.org/math/algebra/exponent-equations/radical_equations/v/extraneous-solutions-to-radical-equations
also @whpalmer4 could you help with this as well
Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions. When f(x) becomes f(x) − 3 When f(x) becomes −2 • f(x)
You can reason these out, and should. You have a function \(f(x)\). Think of it as a little machine that takes a number in (number is represented by \(x\) here), and spits out a number, a unique value for each value of \(x\). Every time you put in a certain value for \(x\), you always get the same number out. You make a little graphing machine which feeds in all sorts of numbers for \(x\), asks the function machine to do its work, and uses the result as \(y\), then puts a dot at that point \((x,y)\). As it does more and more points, you see the shape appear on the plot. With me so far?
yes
Okay. What happens if our machine is a little bit out of adjustment, and each time it plots a point, it plots it at a y value which is 3 less than what came out of the function machine?
Does the result have the same shape?
no
?
right
Uh isn't it going to be the same shape, just shifted by 3 units?
oh yeah it is
Suppose the function is the very simple \(y = f(x) = x\): that's just a straight line with slope 1 passing through the origin and going upward and to the right, up 1 step for each step to the right. If you plot the same thing, but subtract 3 from \(y\) each time, you get a straight line running parallel to the first one, but 3 units lower. It crosses the y axis at (0,-3) instead of (0,0).
oh ok i see it now
Here's another example:
Here are the questions: Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions. What is the effect on the y-intercept? Do we change the regions where the graph is increasing or decreasing? Does the end behavior change?
I have to leave now, so you'll need to work this out by yourself, but I'm confident that you can do so. I'll check back in a few hours.
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