b) Find the value(s) of c that satisfy the conclusion of the MVT for the function f(x) =sqrt(x-1) on the interval [1; 3]. c) How many real roots does the equation x^5 + 2x + 3 = 0 have?
first, do you know what the mean value theorem says?
basically an equation will have a tangent line equal to the average slope of the line
so first lets find the slope of the line in equation
so (0-sqrt2)/1-3
yup so that is \[\sqrt{2}/2\]
yeah
now lets take the derivative of your function
(.5)(x-1)^(-.5)
so 1/sqrtx-1
1/2(ssqrtx-1)
great, so now solve for x when the derivative equals sqrt(2)/2
so plug sqrt2/2 into f'(x)?
f'(sqrt/2)??
not exactly, you are looking for what x value will guve you a derivative of sqrt(2)/2
so solve\[\sqrt{2}/2=1/(2\sqrt{x-1})\]
ok, then what? while i have your attention, haha
then you have your answer
oh i see, so my x value once solves for is my value "c"
then what about the real roots equation, i feel like its just 5, but i don't really know how to prove it
first, tell me what math course you are in because there are a few different ways to go about this problem depending on what course this is in
calc 1
ok. lets think about this, what happens to f(x) as x approaches infinity?
it goes toward infinity
and what about as f(x) approaches negative infinity
negative infinity
ok, good, do you know what an inflection point is?
f''
f''(x)=0
yeah so that is when the derivative is going to change sign (become positive or negative)
can you tell me what the first derivative of this function is?
5x^4 + 2
i have to leave for class in 5 minutes
does that equal zero for any real x value? (we are almost done)
yeah i think it does
since the derivative is always positive here, we know that there arent any dips in the function so it can only cross that x axis once. This means that there is only one real root
x^4 is always postive so 5x^4 +2 is always positive
ohhhhhh
wow
if you look at this http://www.wolframalpha.com/input/?i=x%5E5%2B2x%2B3 you will see that it only crosses the x axis once
so we can use the derivative to see that the function is always increasing
right right, i understand so basically it was asking how many times does it cross the x axis, that makes so much more sense
i get where u are going with the +/- infinity too now, ahha
if it is always increasing from negative infinity to infinity, it will only cross the x axis once
Thank you very much
no prob, enjoy class
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