Question

When solving a radical equation, Beth and Kelly came to two different conclusions. Beth found a solution, while Kelly's solution did not work in the equation.

Create and justify two situations: one situation where Beth is correct and a separate situation where Kelly is correct.

Answer 1

That kind of situations where the solution do not work in the equation is called extraneous solution. You'll find an example here : http://www.mathwords.com/e/extraneous_solution.htm

Answer 2

ok but how can i justify where beth is correct

Answer 3

You have to plug Beth's solution into the equation and see if it checks !

Answer 4

oh ok thanks i have 1 more problem think yu cn help me 1 last time

Answer 5

Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions.


When f(x) becomes f(x) − 3
When f(x) becomes −2 • f(x)

Answer 6

i have been stuck on this question 4 da lonqest

Answer 7

When multiplied by 2 the function shrinks. When f(x) becomes f(x) − 3 the graph move 3 steps to the left.

Answer 8

oh really