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Physics 17 Online
OpenStudy (anonymous):

how much greater is the energy of a photon of ultraviolet radiation (lambda =3.00*10^-7m) than the energy of an average photon of sunlight (lambda= 5.60 *10^-7m)?

OpenStudy (anonymous):

f=c/lambda E=h*f The one who has lower lambda has higher frequency and so grater energy using the Planks formula BA my answer if helped

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