solve 3x^2+18x+15=0 by completing the square
@surjithayer
@AccessDenied
hm
do you know what a perfect square trinomial is?
1.take common 3 2.add the square of half the co-efficient of x.
im confused
\[3\left( x^2+6x \right)+5=0,3\left( x^2+6x+9-9 \right)+5=0\] \[3\left( x^2+6x+9 \right)-27+5=0\] \[3\left( x+3 \right)^2-22=0\] \[\left( x+3 \right)^2=\frac{ 22 }{ 3 },x+3=\pm \sqrt{\frac{ 22 }{ 3 }}\] find x
im still confused
solve 3x^2+18x+15=0 by completing the square: Let's go thru this quickly, with your involvement. Later, we could discuss the why's. 3 is a factor common to all four terms in 3x^2+18x+15=0. Please factor out the 3 right now: 3( ??? )
15/3 = ?
15 x 3 or 15 divided by 3?
I was just trying to help you get started on the necessary factoring.\[\frac{ 15 }{ 3 }=?\]
5
Right. and (3x^2)/3 = ?
3?
\[\frac{ 3x^2 }{ 3 }=?\]Hint: just cancel the 3s.
x^2
Right. and \[\frac{ 18x }{ 3 }=?\]
6
Actually, that'd be 6x. Then 3x^2+18x+15=0 has been factored: 3(x^2 + 6x +5)=0. Look carefully. Does this make sense to you?
yes
Great. Now, we're going to ignore that coefficient 3 for a while, and focus only on x^2 + 6x +5. We're going to do something to x^2 + 6x + 5 called "completing the square." I won't explain a lot right now, but rather will just ask you to do this or that; we'll go into the reasons later if you're interested.
Re-write x^2 + 6x + 5 as x^2 + 6x + 5 Now take the coefficient of x (which is 6); halve it. What do you get? Half of 6 is what?
3
Good. Now please square that 3. 3^2 = ?
9
Right you are! Now take another look at x^2 + 6x + 5 Add your 9 to the right of the 6x term; then subtract 9 from the 1st 9.
huh?
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