Question

Can someone Please help me a medal will be given!
The equation of line EF is y = 1 over 2x + 6. Write an equation of a line parallel to line EF in slope-intercept form that contains point (0, −2).

y = −2x − 2

y = negative 1 over 2x + 2

y = 1 over 2x − 2

y = − 2x + 2

Answer 1

@TuringTest @whpalmer4 @e.mccormick @hoblos

Answer 2

EF is \[y=\frac{1}{2}x+6\]?

Answer 3

I'm going to assume it is. That is a line equation in slope-intercept form, or \[y = mx+b\]where \(m\) is slope and \(b\) is the y-intercept.

You need a parallel line. Parallel lines have the same slope.

Finally, you need to write a parallel line that goes through the point (0,-2). To do that, use the point-slope formula for a line with slope \(m\) going through point \((x_1,y_1)\):
\[y-y_1 = m(x-x_1)\]

After you've written that, solve it for \(y\) and compare with your answer choices.

Answer 4

can you elaborate a little more
@whpalmer4

Answer 5

Ask a specific question. I told you the entire procedure...

Answer 6

Do you understand how to get the slope of the current line?

Answer 7

no and how do i find y-y1

Answer 8

@whpalmer4

Answer 9

You still haven't answered my original question about whether I interpreted your description of the equation correctly.

Answer 10

no @whpalmer4

Answer 11

If that isn't the correct equation, what is? Either use the equation editor button or draw it

Answer 12

wait no you are right @whpalmer4

Answer 13

Okay, thank you.

Compare the equation from the problem with the one beneath it:

\[y = \frac{1}{2}x+6\]\[y=mx+b\]

If they are equal, what are the values of \(m\) and \(b\)?

Answer 14

@whpalmer4 i really dont understand this

Answer 15

You have two equations right over each other. You can't figure out which numbers and which variables correspond?

Answer 16

\[b = 6\]Can you figure out what \(m\) is?

Answer 17

1/2?

Answer 18

Very good! That wasn't so hard, was it?

Answer 19

There are a number of things where you'll do the same operation (comparing two equations, one with numbers and the other with variables, and using the similarity to find the values of the variables) so it's best that you get comfortable with the notion.

Answer 20

So the slope of the line is \(m = \frac{1}2\)

As I said earlier, the point-slope formula will allow us to write the equation of a line with slope \(m\) passing through a point \((x_1,y_1)\). We know that \(m = \frac{1}{2}\), and our known point that the line is to pass through is \((x_1,y_1) = (0,-2)\)

Any question about that?

Answer 21

Okay, so you know \(m, x_1, y_1\), plug them into the formula:
\[y-y_1 = m(x-x_1)\]What do you get?

Answer 22

so how do i find y-y1

Answer 23

@whpalmer4

Answer 24

Take out your pencil. Write "y - "
then write in the value of \(y_1\)

Answer 25

@whpalmer4 and y is 2x?

Answer 26

Geez, you're really not getting this.

\[m = \frac{1}{2}\]\[(x_1,y_1) = (0,-2)\]\[x_1 = 0\]\[y_1 = -2\]

\[y-y_1 = m(x-x_1)\]\[y - (-2) = \frac{1}{2}(x-0)\]\[y+2 = \frac{1}{2}x\]Can you solve that equation for \(y\) on the left, and everything else on the right?

Answer 27

i got y = -1/2 over 2x + 2

Answer 28

@whpalmer4

Answer 29

Can you write out all of the steps you took to produce that result, starting with my equation?

Answer 30

after all i put i got y+2=1/2

the i subtracted two from both sides

Answer 31

What happened to the x?

Answer 32

\[y + 2 = \frac{1}{2}x\]Subtract 2 from both sides:
\[y+2-2 = \frac{1}{2}x - 2\]\[y = \frac{1}{2}x-2\]