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Mathematics 21 Online
OpenStudy (sanra123):

@ganeshie8

OpenStudy (sanra123):

OpenStudy (kc_kennylau):

Which questions?

OpenStudy (sanra123):

3 a)

OpenStudy (kc_kennylau):

Volume of cuboid = length * width * height

OpenStudy (sanra123):

3. a. V = 1/3bh V = length*width*height V= b-5*3b*b+1 V = 15b²-b-1

OpenStudy (sanra123):

correct?

OpenStudy (kc_kennylau):

Nope

OpenStudy (kc_kennylau):

Don't forget the parentheses

OpenStudy (kc_kennylau):

V=(b-5)(3b)(b+1)

OpenStudy (sanra123):

V = 15b²-b-1

OpenStudy (sanra123):

the answer?

OpenStudy (kc_kennylau):

No that's not correct

OpenStudy (sanra123):

how?

OpenStudy (kc_kennylau):

How did you get 15b^2-b-1?

OpenStudy (anonymous):

For 3 a) you wrote: V = length*width*height - this is correct V= b-5*3b*b+1 - this is not correct because you forgot the parentheses. It should be V=(b-5)*(3*b)*(b+1) And the answer to that is going to be V=(b-5)*(3*b)*(b+1)=(3*b^2-15*b)*(b+1)=3*b^3-15*b^2+3*b^2-15*b=3*b^3-12*b^2-15*b or b*(3*b^2-12*b-15) or 3*b*(b^2-4*b-5). Solving the quadratic form inside the parentheses you have the two roots equal to 5 and -1. So the expression now becomes: V=3*b*(b^2-4*b-5=3*b*(b-5)*(b+1). Side note: A quick way to tell whether or not you're right with the answer is to check the polynomial form of your answer. If it's something^2 it's an area (hence why we call it the "square" of a number). If it's something^3 it's a volume (hence why we call it the "cube" of a number).

OpenStudy (sanra123):

@kc_kennylau

OpenStudy (sanra123):

Is that correct for 3/c : C) V = 1/3bh V = 1/3(L*W) h V = 1/3( (2k+3)*(k-2) ) 3k V = k(2k²+3k - 4k - 6) V = k(2k² - k - 6) V = 2k^3 - k^2 - 6k

OpenStudy (sanra123):

@kc_kennylau

OpenStudy (kc_kennylau):

Perfect

OpenStudy (sanra123):

My friend said that the formula is 1/2bhl

OpenStudy (sanra123):

Not 1/3bhl

OpenStudy (sanra123):

@kc_kennylau

OpenStudy (kc_kennylau):

Then tell your friend that he's wrong.

OpenStudy (kc_kennylau):

P.S. 1/2*b*h is for triangle

OpenStudy (sanra123):

Ok thanks that's hat I told her ..

OpenStudy (sanra123):

Thanks

OpenStudy (kc_kennylau):

No problem

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