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OpenStudy (sanra123):
OpenStudy (kc_kennylau):
Which questions?
OpenStudy (sanra123):
3 a)
OpenStudy (kc_kennylau):
Volume of cuboid = length * width * height
OpenStudy (sanra123):
3.
a. V = 1/3bh
V = length*width*height
V= b-5*3b*b+1
V = 15b²-b-1
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OpenStudy (sanra123):
correct?
OpenStudy (kc_kennylau):
Nope
OpenStudy (kc_kennylau):
Don't forget the parentheses
OpenStudy (kc_kennylau):
V=(b-5)(3b)(b+1)
OpenStudy (sanra123):
V = 15b²-b-1
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OpenStudy (sanra123):
the answer?
OpenStudy (kc_kennylau):
No that's not correct
OpenStudy (sanra123):
how?
OpenStudy (kc_kennylau):
How did you get 15b^2-b-1?
OpenStudy (anonymous):
For 3 a) you wrote:
V = length*width*height - this is correct
V= b-5*3b*b+1 - this is not correct because you forgot the parentheses. It should be
V=(b-5)*(3*b)*(b+1)
And the answer to that is going to be
V=(b-5)*(3*b)*(b+1)=(3*b^2-15*b)*(b+1)=3*b^3-15*b^2+3*b^2-15*b=3*b^3-12*b^2-15*b or b*(3*b^2-12*b-15) or 3*b*(b^2-4*b-5).
Solving the quadratic form inside the parentheses you have the two roots equal to 5 and -1. So the expression now becomes:
V=3*b*(b^2-4*b-5=3*b*(b-5)*(b+1).
Side note: A quick way to tell whether or not you're right with the answer is to check the polynomial form of your answer. If it's something^2 it's an area (hence why we call it the "square" of a number). If it's something^3 it's a volume (hence why we call it the "cube" of a number).
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OpenStudy (sanra123):
@kc_kennylau
OpenStudy (sanra123):
Is that correct for 3/c :
C) V = 1/3bh
V = 1/3(L*W) h
V = 1/3( (2k+3)*(k-2) ) 3k
V = k(2k²+3k - 4k - 6)
V = k(2k² - k - 6)
V = 2k^3 - k^2 - 6k
OpenStudy (sanra123):
@kc_kennylau
OpenStudy (kc_kennylau):
Perfect
OpenStudy (sanra123):
My friend said that the formula is 1/2bhl
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OpenStudy (sanra123):
Not 1/3bhl
OpenStudy (sanra123):
@kc_kennylau
OpenStudy (kc_kennylau):
Then tell your friend that he's wrong.
OpenStudy (kc_kennylau):
P.S. 1/2*b*h is for triangle
OpenStudy (sanra123):
Ok thanks that's hat I told her ..
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