Question

how to use the gradient from the velocity vs tan angle graph to find the value of g ( gravity) ?????

Answer 1

@Mashy

Answer 2

so magnitude of velocity vs Tangent of the angle, that the velocity makes with x axis or something?

Answer 3

i have never worked with such graphs :D

Answer 4

so u don't know how to work out g ( gravity ) form the gradient ?

Answer 5

I am not sure i understand the question

your graph.. tell me what does it have along y axis nd along x axis?

Answer 6

y is the velocity and on the x-axis is the Tangent of the angle,

Answer 7

angle between what?!

Answer 8

Besides what sort of graph is that.. i have nEver heard of something like that before.. why do you even use that o.O

Answer 9

Ohhww.. are you talking about circular motion!?

Answer 10

i really have no clue.. u better ask for someone else :P

Answer 11

ok

Answer 12

thats derivative

Answer 13

This is your answer .... @RANE

Answer 14

the formula for the gravity is \[g = \frac{ v ^{2} }{ r \tan \theta } \]

Answer 15

how is the value of the gradient can be used in this equation ?

Answer 16

Ok Hold ... I will tell you ....

Answer 17

ok

Answer 18

@RANE I can't find the answer ..... Your question is too critical ....

Answer 19

oh

Answer 20

May be you can find your answer in Google ....

Answer 21

its not there i have tried it

Answer 22

Then I think so there is no answer of this question ....

Answer 23

there has to be
its a lab report

Answer 24

Then I prefer you that contact any lab .... :P

Answer 25

lol, i wish

Answer 26

I'm sorry but I'm not good with physics and its late for me and I'm tired :P
Not many physics masters are on atm but these are some :3
@Callisto

@whpalmer4

@hoblos

@wolfe8

Answer 27

If your equation is correct then
Tan theta = v^2/rg

If you plot tan theta against V^2/r then you should have a straight line - the gradient will be 1/g

(Note : r = L cosTheta)

I know that his is not what you asked but - since the graph you describe is a curve it does not have a general value for gradient.

Answer 28

i didn't say it a curve or anything like that but ust to tell you its straight line

Answer 29

@RANE @MrNood @ShadowLegendX
I want to say that there is no answer ..... So,please Don't waste your Time ... :P

Answer 30

@arslanfarooka some of my class mates have done it
there is an an

Answer 31

answer*

Answer 32

I do my best But I can't find the answer .... I will Contact my professor Then I shall tell you the proper answer .... Is that ok ...

Answer 33

no its fine thanks for your concern

Answer 34

@arslanfarooka On what basis do you say there is not an answer?

If the data exists and the formula is correct then even if there is not an analytical solution there must be an empirical one...

Answer 35

@MrNood Bro In this question there is no data exists and have no formula then what kind of method that we used to find the proper answer .... tell me hannn ... :@

Answer 36

ok guys relax pls,we r not here to discuss or argue weather these is formula or not
but wht is the way to solve it

Answer 37

@RANE The only way to solve this that you contact your professor or your seniors .... Got it .... @RANE If you find the answer then please Inboxed me ... :)

Answer 38

ok i will

Answer 39

OK - I have looked at the diagram - I think I see what this is -

You are measuring the speed of circular motion over different length of string

If oyu resolve the tension (T) in the string:

Vertically Tcos thets = mg
Horizontally Tsintheta = mv^2/r (centripetal force)

Divide the 2 equations and you get Tan Theta = v^2/rg

This is how your equation is derived , and shows that the equation is correct.

SO
gTan theta = v^2/r

Answer 40

Now - the eqation of a STRAIGHT line is y = mx +c
where m is the gradient
on your graph y is V and x is tan theta

For circular motion v = r w (w= omega= angular velocity)

so v^2 /r = w^2

so gtan theta= w^2

In order to make this a straight line you need to plot w^2 in Y and tan theta in x

I cannot see how v against tan theta can be a straight line

Answer 41

Correction

v = rw v^2= r^2 w^2

therefore v^/r = rw^2

Answer 42

@MrNood ok fine bro u won :)

Answer 43

thats not th right way
but thanks anyway
u told me a hard and long way , thank again

Answer 44

@RANE r u find the answer ...???

Answer 45

yh i have figured it out

Answer 46

@rane care to post it for our education?

I'd like to understand the solution....

Answer 47

@rane send me answer in inbox