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Mathematics 22 Online
OpenStudy (anonymous):

medal! fan! please help

OpenStudy (anonymous):

A. The price of the cups, p(x), is a function of the number of x cups ordered. Using the table, determine the average rate of change for the first 1,000 cups ordered and then for all 3,000 cups ordered. What does this tell you about the function?

OpenStudy (anonymous):

OpenStudy (anonymous):

i dont wana cheat. i dont know how to find it. i need like an explanation and stuff

OpenStudy (mathmale):

If f(x) is a function defined on a certain interval, then the "average rate of change" is given by \[ave.rate.of.change=\frac{ f(b)-f(a) }{ b-a }\]where a=left endpoint of interval, and b=right endpoint of interval.

OpenStudy (mathmale):

Here, we have a table of x- and y-values instead of a function f(x). For the first 1000 cups, a=0 and b=1000. What are the corresponding f(a) and f(b)?

OpenStudy (anonymous):

i think i already have it actually. i had my cousin help me. leme show you waht i got

OpenStudy (anonymous):

OpenStudy (mathmale):

This problem has two parts. The first part asks you to find the average rate of change of the function represented by the graph, for the interval [0,1000]. Where is your calculation for that?

OpenStudy (anonymous):

i pluged every thing in...into y-y/x-x...

OpenStudy (mathmale):

I'd like to see the following: f(1000) - f(0) ---------- = average rate of change on the interval [0,1000] 1000 - 0

OpenStudy (mathmale):

What is the function value when x = 0? What is the function value when x = 1000?

OpenStudy (anonymous):

7......44

OpenStudy (mathmale):

Ave. rate of change on the interval [0,1000] is 44 - 7 ARC = --------- = ? 1000 - 0

OpenStudy (anonymous):

0.037

OpenStudy (mathmale):

that's right. This is the average rate of change of your function on [0,1000]. Now, where is your average rate of change of your function on [0,3000]?

OpenStudy (mathmale):

I'd like to see your calculations.

OpenStudy (anonymous):

\[\frac{ 118-7 }{ 3000-0 }=\frac{ 111 }{ 3000 }= 0.037\]

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