The coordinates of the three vertices of a square ABCD are A (-3, 5), B (1, 7), and C (3, 3).

What are the coordinates of vertex D?
A. (-4, 2)
B. (-2, 1)
C. (-1, 1)
D. (-4,-2)

Question

The coordinates of the three vertices of a square ABCD are A (-3, 5), B (1, 7), and C (3, 3).


What are the coordinates of vertex D?
A. (-4, 2)
B. (-2, 1)
C. (-1, 1)
D. (-4,-2)

anonymous · Answer

Can anyone help....??

anonymous · Answer

let us consider coordinate of D be(x,y)
now determine AB and CD
using the formula
$$\sqrt{(x1-x2)^2 + (y1-y2)^2}$$

anonymous · Answer

then equate AB = CD ( as side of square are equal)

anonymous · Answer

yes. i did that and got about 4.5 as the distance

anonymous · Answer

What do you mean equate? @niksva

anonymous · Answer

equate means equivalent or compare ,etc..

anonymous · Answer

okay, so what do i do next?

anonymous · Answer

mid points of diagonals are same.
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