Question

How many grams of calcium phosphate are theoretically produced if we start with 10.3 moles of Ca(NO3)2 and 7.6 moles of Li3PO4?
Reaction: 3Ca(NO3)2 + 2Li3PO4 → 6LiNO3 + Ca3(PO4)2

Answer 1

@iPwnBunnies

Answer 2

Use stoichiometry (mole ratios) to figure out the limiting reactant.

Answer 3

For the first one,
(10.3 mol Ca(NO3)2)*(1 mol Ca3(PO4)2/3 Ca(NO3)2)

Answer 4

I got the mole ratio from the balanced equation. Ideally, 3 moles of Ca(NO3)2 makes 1 mole of Ca3(PO4)2

Answer 5

I'm confused on how to find the answer still?

Answer 6

We're trying to find which reactant (the stuff on the left) will give us the LEAST amount of Ca3(PO4)2

Answer 7

Because it is the limiting reactant. We can only make so much product if one of the ingredients is used up.

Answer 8

ok....

Answer 9

I like to use it with a cake analogy. Say a cake needs 2 eggs and 3 cups of flour. If we only have 1 egg and unlimited flour, we can still only make a half a cake! T.T

Answer 10

So we have to find the "limited ingredient" that can make our calcium phosphate

Answer 11

For Ca3(NO3)2, it would be this: (10.3 mol Ca(NO3)2)*(1 mol Ca3(PO4)2/3 Ca(NO3)2)

Answer 12

For Li3PO4, it would be this:
\[(7.6 mol)*(\frac{1 mol Ca3(PO4)2}{2 mol Li3PO4})\]

Answer 13

2.3 moles of Ca3(PO4)2 will be produced( 713g).

Answer 14

Did you check both of the reactants?

Answer 15

I got 3.43 mol of Ca3(NO3)2 will be produced.

Answer 16

I'm sure yours is right lol

Answer 17

Lol, it'll be 10.3 mols of the Ca(NO2)3 / 3 = 3.43 mol.
Then multiply 3.43 mol of Ca3(PO4)2 by its molar mass to get the mass.

Answer 18

So my end answer is the 3.43 mol of Ca3(NO3)2?

Answer 19

No, it asks you how many grams of product do we get.

Answer 20

Figure out the molar mass of Ca3(PO4)2, because that's the product, and multiply it by the amount of moles of it that we have, 3.43 mol.

Answer 21

3.43*310 = 1063.3 g

Answer 22

@iPwnBunnies

Answer 23

I got 372.12 g/mol as the molar mass. :o

Answer 24

Oops, I messed up this time. ;.; Hold on lol.

Answer 25

Yes, you are right. When doing problems similar to this, think of the cake analogy. :D

Answer 26

Woo So all I write is 1063.3 g Ca3(PO4)2

Answer 27

I believe so.

Answer 28

Can I tag you in more? I have to hurry before I leave for work lol

Answer 29

Ugh, I'm not gonna solve them for you quick. Try to do it when you have time. Just follow my steps, practice makes perfect. If you need help, you can tag me.

Answer 30

I'm not asking you to solve them for me.. I was just wondering if you could double check a couple for me.