Ross is analyzing a circle, y2 + x2 = 64, and a linear function g(x). Will they intersect?
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
g(x) is a linear function, so we just need the slope and a point on this line to find the equation
jimthompson5910 (jim_thompson5910):
what's the slope of g(x)?
OpenStudy (anonymous):
One sec
jimthompson5910 (jim_thompson5910):
alright
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OpenStudy (anonymous):
The slope is .5?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
what's the y-intercept?
OpenStudy (anonymous):
-4?
jimthompson5910 (jim_thompson5910):
or (0,-4), good
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jimthompson5910 (jim_thompson5910):
so what's the equation of g(x)?
OpenStudy (anonymous):
g(x)=.5(-4)^x?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
linear equations are of the form y = mx + b
jimthompson5910 (jim_thompson5910):
m is the slope
b is the y-intercept
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OpenStudy (anonymous):
no
but the line goes through the point \((0,-4)\) which is inside the circle
jimthompson5910 (jim_thompson5910):
that's a good point, if you have a point in the circle (that lies on the line), then the line has to cross through the circle since it goes on forever
but it often helps to figure out the equation
OpenStudy (anonymous):
g(x)=.5(-1)-4?
jimthompson5910 (jim_thompson5910):
more like g(x) = 0.5x - 4
jimthompson5910 (jim_thompson5910):
since m = 0.5 (slope) and b = -4 (y-intercept)
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OpenStudy (anonymous):
Oh ok. Let me graph them to see if they intersect at more than one point
OpenStudy (anonymous):
Ok so they intersect at both a negative and a positive x-coordinate?
jimthompson5910 (jim_thompson5910):
that is correct
OpenStudy (anonymous):
Awesome. Thanks Jim :)
jimthompson5910 (jim_thompson5910):
sure thing
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OpenStudy (anonymous):
@jim_thompson5910 what if the line intersects with the circle when x=0, will the answer still be they intersect at both a negative and a positive x-coordinate, if 0 is neither positive nor negative?!