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OpenStudy (anonymous):
If 0.461 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced in the following reaction?
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OpenStudy (anonymous):
moles of zinc to moles of zinc sulfate, moles of zinc sulfate to grams. 0.461 mol Zn * (2 mol ZnSO4 / 2 mol Zn) * (161.45 g ZnSO4 / 1 mol ZnSO4) = 74.43 g ZnSO4
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