Question

need help putting this together

Answer 1

@phi

Answer 2

If we assume the boat ends up going straight across (i.e. heading 20º upstream compensates for the current carrying it downstream), its resultant velocity is 7 cos(20)

Answer 3

6.58

Answer 4

I am sorry. I forgot

Answer 5

@phi

Answer 6

Is there any more info for this question? Do they give the speed of the current ?
If not, we have to make assumptions.

Answer 7

@phi they give the miles per hour which was 7 and the degree wich was 20 and you decided that that was going to be 7cos of20 in which i get 6.58 but then it also gives a width of 132 so what do we do with that?

Answer 8

i'm unsure of what to do from there

Answer 9

Nothing, unless there is more to the question (which I assume there is)

Answer 10

it says find the the velocity of the bank which we've done so yes we don't do anything else

Answer 11

Notice that I am guessing about that answer. If the river is not flowing at all, the boat is moving at a speed of 7 m/hr....

Answer 12

yes

Answer 13

it makes since now seeing that the boat is the only thing moving. Thanks for the help.

Answer 14

there was a piece missing to the equation @phi

Answer 15

sorry about that

Answer 16

break your "boat" vector into two parts
directly across x and directly upstream y
x = 7 cos(20)
y = 7 sin(20)
add -3 to the y component.
now find the magnitude of the new vector

Answer 17

i was thinking that. my answer is 6.6

Answer 18

yes, that is what I get. so the boat is moving at a speed of 6.6 m/h

Answer 19

thank you again for your time aand help.

Answer 20

yw