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Mathematics 7 Online
OpenStudy (anonymous):

A soft drink machine is regulated so that the amount of drink it dispenses follows a normal distribution with a known standard deviation of the drinks dispensed of 20 milliliters. A random sample of 30 drinks from the machine had an average volume of 373 milliliters. Determine a 95% confidence interval for the average amount of all drinks dispensed by this machine. Here I know the formula for confidence intervals but not sure of how to proceed with the question. Can any 1 help me out?

ganeshie8 (ganeshie8):

lets list out whats given : \(\sigma = 20\) \(n = 30\) \(\overline{x} = 373\)

ganeshie8 (ganeshie8):

Confidence interval = \(\large \overline{x} \pm Z^* \frac{\sigma}{\sqrt{n}}\)

ganeshie8 (ganeshie8):

simply plugin the values

OpenStudy (anonymous):

oh....simple calculation. But is there any specific table for calculating confidence interval....I have no idea.

ganeshie8 (ganeshie8):

yes :) http://www.math.upenn.edu/~chhays/zscoretable.pdf

ganeshie8 (ganeshie8):

look at the zscore value when the area is approximately \(0.95\)

OpenStudy (anonymous):

thanks a lot. I have to solve many problems based on confidence intervals...it will be useful for me!!!

ganeshie8 (ganeshie8):

ack.. I was wrong earlier, for 95% CI, the zscore is \(1.64\)

ganeshie8 (ganeshie8):

so, \(\large Z^* = 1.64\)

ganeshie8 (ganeshie8):

np :)

ganeshie8 (ganeshie8):

OpenStudy (anonymous):

ok....ty!!!!

OpenStudy (anonymous):

I have one more concern....what happens if the 30 samples alone has different standard deviation. Should we calculate the confidence interval for both and subtract it?

ganeshie8 (ganeshie8):

good question :)

ganeshie8 (ganeshie8):

let me rephrase ur question a bit

ganeshie8 (ganeshie8):

you're asking :- "If we know both population standard deviation and the sample standard deviation, which one we need to use for computing Confidence Intervals ?"

ganeshie8 (ganeshie8):

thats the question, right ?

OpenStudy (anonymous):

spot on!!!!!!

ganeshie8 (ganeshie8):

If the population is not too much skewed, then the sample standard deviation should MATCH almost perfectly with population standard deviaiton

ganeshie8 (ganeshie8):

here is the rule of thumb :- if you knw populaiton standard deviation, USE it !! if you dont knw population standard deviaition, compute standard deviation from sample

ganeshie8 (ganeshie8):

In general, you will not have access to populaiton parameters... cuz when u do surveys u wont knw upfront what their mean/standard deviation will be

ganeshie8 (ganeshie8):

so we will be computing sample standard deviation almost all the time

OpenStudy (anonymous):

say, if both population S.D and sample S.D are given in a problem....what should we do??

OpenStudy (anonymous):

say, sample SD is 20 and population SD is 23. should we solve the problem with sample SD?

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