Question

Power series question

Answer 1

Use the geometric series:

\[\sum_{n=0}^{\infty}\frac{ 1 }{ 1-x }\] to find the power series about x=0 for:

\[\frac{ 1-x^2 }{ (1-x)^2 }\]

Answer 2

Kinda stuck on how I manipulate this.

Answer 3

have you tried factoring the numerator? perhaps one of those factors will cancel for you

Answer 4

Well actually, would it be wrong for me to factor the denominator and cancel the numerator?

Answer 5

the denominator is already factored, pretty much: (1 - x )^2 = (1 - x)(1 - x)
the numerator isn't, though!

Answer 6

Ahh okay so one of the terms cancel I see.