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Mathematics 8 Online
OpenStudy (anonymous):

inflection point of x^lnx

OpenStudy (anonymous):

anyone please help!

OpenStudy (anonymous):

do you know logarithmic differentiation?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

y = x^ln(x), then what?

OpenStudy (anonymous):

(i found the first derivative which is (2lnx/x)x^lnx but then deriveing it again is trouble for me

OpenStudy (anonymous):

product rule

OpenStudy (anonymous):

but i did it a few times and got differnt answers

OpenStudy (anonymous):

here is a formula (fgh)' = f' gh + f g' h + fg h' (2lnx/x)x^lnx = (2lnx) (1/x) x^ln(x) derivative of that is: (2/x) (1/x) x^ln(x) + (2lnx) (-1/x^2) x^ln(x) + (2lnx) (1/x) (2lnx) (1/x) x^ln(x) now simplify

OpenStudy (anonymous):

ok let me see if one of my answers the same

OpenStudy (anonymous):

(2x^lnx) (1/x^2) (2ln^2(x) - ln(x) + 1)

OpenStudy (anonymous):

i got (x^lnx) (2-2lnx+4ln^2(x))/x^2

OpenStudy (anonymous):

samething if you were to factor out 2

OpenStudy (anonymous):

oh ok sorry! so now i solve for x when i set this to zero right

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

ok im sure im going to need help with this too please

OpenStudy (anonymous):

its just that i make minor mistakes that have big affects

OpenStudy (anonymous):

ok im stuck at where i divide by 2x^lnx then have 1-lnx+2lnx^2=0

OpenStudy (anonymous):

i got next -lnx+2lnx^v=-1 then im stuck

OpenStudy (anonymous):

can you solve 2u^2 - u + 1 = 0?

OpenStudy (anonymous):

oh yes so we will get two answers?

OpenStudy (anonymous):

i don't know. What does the quadratic formula say?

OpenStudy (anonymous):

i dont know how to do it with lns

OpenStudy (anonymous):

i could set u=lnx but thedn?

OpenStudy (anonymous):

ln(x) = u = 1 +/- sqrt(1 - 4(2)(1)) -------------------- 2(2)

OpenStudy (anonymous):

the determinant is negative, thus, there is no solution. So, f'(x) will never be equal to 0, so there is no inflection point

OpenStudy (anonymous):

ohhhh oh

OpenStudy (anonymous):

how to determine concavity then by looking at graph

OpenStudy (anonymous):

since x > 0, plug in any positive number, say 1, in for x in f''(x) and see what the sign is. f''(x) > 0 means concave up. Otherwise, concave down

OpenStudy (anonymous):

its concave up

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can you help me with anothere one please

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

y

OpenStudy (anonymous):

tired

OpenStudy (anonymous):

of what

OpenStudy (anonymous):

can i ask you a general question please

OpenStudy (anonymous):

not about math just random

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

why do you help people online, with math stuff?

OpenStudy (anonymous):

for fun

OpenStudy (anonymous):

oh ok! where do you live? i sound like a creep but i promise its just curiosity lol

OpenStudy (anonymous):

Arizona, US

OpenStudy (anonymous):

OMG wow im in california, are you a girl?

OpenStudy (anonymous):

no a guy

OpenStudy (anonymous):

ok im a girl aha

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

are u in college?

OpenStudy (anonymous):

hey i see you helping others thts not fair!! ahah joking thanks for ur help!

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