Question

Calculate mass percent of carbon hydrogen and oxygen in glucose

Answer 1

C6 = 12x6 = 90
H12 = 12 x 1 = 12
O6 = 6 x 16 = 96

C6H12O6 = 90 + 12 + 96 = 198

C = (90/198) x 100 = 45.45%
H = (12/198) x 100 = 6.06%
O = (96/198) x 100 = 48.48%

Answer 2

Molar mass of glucose is 180.156
Mass percent of Carbon: 6* 12.01 / 180.156 = 0.399986678 = 40 %
Oxygen and Hydrogen in the same way