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A spring has a spring stiffness constant, k, of 440 N/m. How much must this spring be stretched to store 25 J of potential energy?
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potential energy of spring= 1/2 k x^2 25= 1/2 *440* x^2
0.337099931= x ?
maybe..
when I answered your equation...thats tha answer ive got..
i said maybe...coz that was a lot of calculation there.....and its correct
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okay,,,thank you anyway
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