Given that:

$$\int\limits_{0}^{3} 1/3 f(x) dx = 5 $$

find the value of:

$$\int\limits_{3}^{0} f(x) dx $$

Question

Given that:

 $$\int\limits_{0}^{3} 1/3 f(x) dx = 5 $$ 

find the value of:

 $$\int\limits_{3}^{0} f(x) dx $$

ikram002p · Answer

$\color{blue}{\Huge \int\limits_{0}^{3} \frac{1}{3} f(x) dx = 5}$

$\large \int\limits_{0}^{3} \frac{1}{3} f(x) dx =- \int\limits_{3}^{0} \frac{1}{3} f(x) dx$
=$\large-\frac{1}{3} \int\limits_{3}^{0}  f(x) dx$

ikram002p · Answer

$\large -\frac{1}{3}\int\limits_{0}^{3} f(x) dx = 5 $
$\large \int\limits_{0}^{3} f(x) dx = -5×3=-15 $ 
got it ?

anonymous · Answer

understand. but where the negative 1/3 come from? is it bcz we turn it upside down so automatically it become negative integer

ikram002p · Answer

yess ur correct !

anonymous · Answer

wah, tq tq tq. u help me alot.

ikram002p · Answer

np, ur wlc ^^