Question

Given that:

\[\int\limits_{0}^{3} 1/3 f(x) dx = 5 \]

find the value of:

\[\int\limits_{3}^{0} f(x) dx \]

Answer 1

\(\color{blue}{\Huge \int\limits_{0}^{3} \frac{1}{3} f(x) dx = 5}\)

\(\large \int\limits_{0}^{3} \frac{1}{3} f(x) dx =- \int\limits_{3}^{0} \frac{1}{3} f(x) dx\)
=\(\large-\frac{1}{3} \int\limits_{3}^{0} f(x) dx\)

Answer 2

\(\large -\frac{1}{3}\int\limits_{0}^{3} f(x) dx = 5 \)
\(\large \int\limits_{0}^{3} f(x) dx = -5×3=-15 \)
got it ?

Answer 3

understand. but where the negative 1/3 come from? is it bcz we turn it upside down so automatically it become negative integer

Answer 4

yess ur correct !

Answer 5

wah, tq tq tq. u help me alot.

Answer 6

np, ur wlc ^^